Mixing
Flutter: extend a class by having to implement a method
0
Since I have two similar classes, but with little differences in only one function, I want to create a base class that they will extend, but that will also force them to implement that specific function. To better explain this:
class A {
void print() {print "hello";}
void func (){}
}
class B extends A {
@override func(){
//TODO
}
}
dart
flutter override extends asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
add a comment |
0
Since I have two similar classes, but with little differences in only one function, I want to create a base class that they will extend, but that will also force them to implement that specific function. To better explain this:
class A {
void print() {print "hello";}
void func (){}
}
class B extends A {
@override func(){
//TODO
}
}
dart
flutter override extends asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
add a comment |
0
0
0
Since I have two similar classes, but with little differences in only one function, I want to create a base class that they will extend, but that will also force them to implement that specific function. To better explain this:
class A {
void print() {print "hello";}
void func (){}
}
class B extends A {
@override func(){
//TODO
}
}
dart
flutter override extends asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
Since I have two similar classes, but with little differences in only one function, I want to create a base class that they will extend, but that will also force them to implement that specific function. To better explain this:
class A {
void print() {print "hello";}
void func (){}
}
class B extends A {
@override func(){
//TODO
}
}
dart
flutter override extends dart
flutter override extends asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
asked Jan 1 at 11:50
Little MonkeyLittle Monkey
19812
19812
add a comment |
add a comment |
1 Answer
1
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oldest
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2
you can use an abstract base class, that is the parent of both classes
abstract class Base {
void func();
}
class A extends Base{
@override
void func() {
}
}
class B extends Base {
@override
void func() {
}
}
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
you can use an abstract base class, that is the parent of both classes
abstract class Base {
void func();
}
class A extends Base{
@override
void func() {
}
}
class B extends Base {
@override
void func() {
}
}
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
add a comment |
2
you can use an abstract base class, that is the parent of both classes
abstract class Base {
void func();
}
class A extends Base{
@override
void func() {
}
}
class B extends Base {
@override
void func() {
}
}
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
add a comment |
2
2
2
you can use an abstract base class, that is the parent of both classes
abstract class Base {
void func();
}
class A extends Base{
@override
void func() {
}
}
class B extends Base {
@override
void func() {
}
}
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
you can use an abstract base class, that is the parent of both classes
abstract class Base {
void func();
}
class A extends Base{
@override
void func() {
}
}
class B extends Base {
@override
void func() {
}
}
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
answered Jan 1 at 12:26
Sami KanafaniSami Kanafani
1,008613
1,008613
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
add a comment |
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
I did a great mistake. I was writing "void func(){}" instead of "void func();" in the Base class, so the A class didn't complain about missing implementation. Thanks!
– Little Monkey
Jan 1 at 12:45
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
@LittleMonkey welcome
– Sami Kanafani
Jan 1 at 12:46
add a comment |
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