Kähler Potential on Blowup of $mathbb{C}/{pm 1}$












1












$begingroup$


The book Joyce: Riemannian Holonomy Groups and Calibrated Geometry contains on page 205 the Eguchi-Hanson space as an example:




Consider $mathbb{C}^2$ with complex coordinates $(z_1,z_2)$, acted upon by the involution $-1:(z_1,z_2) mapsto (-z_1,-z_2)$.
Let $(X,pi)$ be the blow-up of $mathbb{C}^2/{pm 1}$ at $0$.
Then $X$ is a crepant resolution of $mathbb{C}^2/{pm 1}$.
(...)
Define $f:X setminus pi^{-1}(0) rightarrow mathbb{R}$ by
$$
f=
sqrt{r^4+1}+2 log r - log left( sqrt{r^4+1} +1 right),
$$

where $r=left( |z_1|^2 + |z_2 |^2 right)^{1/2}$ is the radius function on $X$.



Define a $2$-form $omega_1$ on $X setminus pi^{-1}(0)$ by $omega_1=i partial overline{partial} f$.
Then $omega_1$ extends smoothly and uniquely to $X$.




Question:




How can I see that $omega_1$ extends to $X$?




Writing $r= sqrt{z_1 overline{z_1}+z_2 overline{z_2}}$ I can compute $omega_1$ explicitly.
The expressions are long, so I used Mathematica.
All partial derivatives $frac{partial}{partial overline{z_i}}frac{partial}{partial z_k}f$ tend to $infty$ as $r rightarrow 0$.
So it seems to me as if $f$ cannot be extended.
What am I missing?










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    The book Joyce: Riemannian Holonomy Groups and Calibrated Geometry contains on page 205 the Eguchi-Hanson space as an example:




    Consider $mathbb{C}^2$ with complex coordinates $(z_1,z_2)$, acted upon by the involution $-1:(z_1,z_2) mapsto (-z_1,-z_2)$.
    Let $(X,pi)$ be the blow-up of $mathbb{C}^2/{pm 1}$ at $0$.
    Then $X$ is a crepant resolution of $mathbb{C}^2/{pm 1}$.
    (...)
    Define $f:X setminus pi^{-1}(0) rightarrow mathbb{R}$ by
    $$
    f=
    sqrt{r^4+1}+2 log r - log left( sqrt{r^4+1} +1 right),
    $$

    where $r=left( |z_1|^2 + |z_2 |^2 right)^{1/2}$ is the radius function on $X$.



    Define a $2$-form $omega_1$ on $X setminus pi^{-1}(0)$ by $omega_1=i partial overline{partial} f$.
    Then $omega_1$ extends smoothly and uniquely to $X$.




    Question:




    How can I see that $omega_1$ extends to $X$?




    Writing $r= sqrt{z_1 overline{z_1}+z_2 overline{z_2}}$ I can compute $omega_1$ explicitly.
    The expressions are long, so I used Mathematica.
    All partial derivatives $frac{partial}{partial overline{z_i}}frac{partial}{partial z_k}f$ tend to $infty$ as $r rightarrow 0$.
    So it seems to me as if $f$ cannot be extended.
    What am I missing?










    share|cite|improve this question









    $endgroup$















      1












      1








      1


      2



      $begingroup$


      The book Joyce: Riemannian Holonomy Groups and Calibrated Geometry contains on page 205 the Eguchi-Hanson space as an example:




      Consider $mathbb{C}^2$ with complex coordinates $(z_1,z_2)$, acted upon by the involution $-1:(z_1,z_2) mapsto (-z_1,-z_2)$.
      Let $(X,pi)$ be the blow-up of $mathbb{C}^2/{pm 1}$ at $0$.
      Then $X$ is a crepant resolution of $mathbb{C}^2/{pm 1}$.
      (...)
      Define $f:X setminus pi^{-1}(0) rightarrow mathbb{R}$ by
      $$
      f=
      sqrt{r^4+1}+2 log r - log left( sqrt{r^4+1} +1 right),
      $$

      where $r=left( |z_1|^2 + |z_2 |^2 right)^{1/2}$ is the radius function on $X$.



      Define a $2$-form $omega_1$ on $X setminus pi^{-1}(0)$ by $omega_1=i partial overline{partial} f$.
      Then $omega_1$ extends smoothly and uniquely to $X$.




      Question:




      How can I see that $omega_1$ extends to $X$?




      Writing $r= sqrt{z_1 overline{z_1}+z_2 overline{z_2}}$ I can compute $omega_1$ explicitly.
      The expressions are long, so I used Mathematica.
      All partial derivatives $frac{partial}{partial overline{z_i}}frac{partial}{partial z_k}f$ tend to $infty$ as $r rightarrow 0$.
      So it seems to me as if $f$ cannot be extended.
      What am I missing?










      share|cite|improve this question









      $endgroup$




      The book Joyce: Riemannian Holonomy Groups and Calibrated Geometry contains on page 205 the Eguchi-Hanson space as an example:




      Consider $mathbb{C}^2$ with complex coordinates $(z_1,z_2)$, acted upon by the involution $-1:(z_1,z_2) mapsto (-z_1,-z_2)$.
      Let $(X,pi)$ be the blow-up of $mathbb{C}^2/{pm 1}$ at $0$.
      Then $X$ is a crepant resolution of $mathbb{C}^2/{pm 1}$.
      (...)
      Define $f:X setminus pi^{-1}(0) rightarrow mathbb{R}$ by
      $$
      f=
      sqrt{r^4+1}+2 log r - log left( sqrt{r^4+1} +1 right),
      $$

      where $r=left( |z_1|^2 + |z_2 |^2 right)^{1/2}$ is the radius function on $X$.



      Define a $2$-form $omega_1$ on $X setminus pi^{-1}(0)$ by $omega_1=i partial overline{partial} f$.
      Then $omega_1$ extends smoothly and uniquely to $X$.




      Question:




      How can I see that $omega_1$ extends to $X$?




      Writing $r= sqrt{z_1 overline{z_1}+z_2 overline{z_2}}$ I can compute $omega_1$ explicitly.
      The expressions are long, so I used Mathematica.
      All partial derivatives $frac{partial}{partial overline{z_i}}frac{partial}{partial z_k}f$ tend to $infty$ as $r rightarrow 0$.
      So it seems to me as if $f$ cannot be extended.
      What am I missing?







      differential-geometry complex-geometry kahler-manifolds k3-surfaces






      share|cite|improve this question













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      asked Jan 25 at 21:50









      user505117user505117

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