Mixing
react native how to filter JSON
1
This is my local JSON file (JsonData.json):
{
"Phone": [
{
"num": "phone1",
"name": "galaxy",
"temp": [
"5",
"6"
],
"id": 1
},
{
"num": "phone2",
"name": "iPhone",
"temp": [
"4",
"5",
"6"
],
"id": 2
},
…
],
"Computer": [
{
"num": "computer1",
"name": "Mac",
"temp": [
"1"
],
"id": 1
},
{
"num": "computer2",
"name": "Samsung",
"temp": [
"4"
],
"id": 2
},
…
]
}
And I imported it this way (I've been correctly using it):
var JsonData = require('./JsonData.json');
I want to get a name (galaxy, iPhone...) when temp = "4", from both phone and computer data.
How can I get them?
json react-native
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
add a comment |
1
This is my local JSON file (JsonData.json):
{
"Phone": [
{
"num": "phone1",
"name": "galaxy",
"temp": [
"5",
"6"
],
"id": 1
},
{
"num": "phone2",
"name": "iPhone",
"temp": [
"4",
"5",
"6"
],
"id": 2
},
…
],
"Computer": [
{
"num": "computer1",
"name": "Mac",
"temp": [
"1"
],
"id": 1
},
{
"num": "computer2",
"name": "Samsung",
"temp": [
"4"
],
"id": 2
},
…
]
}
And I imported it this way (I've been correctly using it):
var JsonData = require('./JsonData.json');
I want to get a name (galaxy, iPhone...) when temp = "4", from both phone and computer data.
How can I get them?
json react-native
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
add a comment |
1
1
1
1
This is my local JSON file (JsonData.json):
{
"Phone": [
{
"num": "phone1",
"name": "galaxy",
"temp": [
"5",
"6"
],
"id": 1
},
{
"num": "phone2",
"name": "iPhone",
"temp": [
"4",
"5",
"6"
],
"id": 2
},
…
],
"Computer": [
{
"num": "computer1",
"name": "Mac",
"temp": [
"1"
],
"id": 1
},
{
"num": "computer2",
"name": "Samsung",
"temp": [
"4"
],
"id": 2
},
…
]
}
And I imported it this way (I've been correctly using it):
var JsonData = require('./JsonData.json');
I want to get a name (galaxy, iPhone...) when temp = "4", from both phone and computer data.
How can I get them?
json react-native
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
This is my local JSON file (JsonData.json):
{
"Phone": [
{
"num": "phone1",
"name": "galaxy",
"temp": [
"5",
"6"
],
"id": 1
},
{
"num": "phone2",
"name": "iPhone",
"temp": [
"4",
"5",
"6"
],
"id": 2
},
…
],
"Computer": [
{
"num": "computer1",
"name": "Mac",
"temp": [
"1"
],
"id": 1
},
{
"num": "computer2",
"name": "Samsung",
"temp": [
"4"
],
"id": 2
},
…
]
}
And I imported it this way (I've been correctly using it):
var JsonData = require('./JsonData.json');
I want to get a name (galaxy, iPhone...) when temp = "4", from both phone and computer data.
How can I get them?
json react-native
json react-native
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
edited Nov 22 '18 at 12:16
c-chavez
2,34221833
2,34221833
asked Nov 22 '18 at 11:57
elloello
154
asked Nov 22 '18 at 11:57
elloello
154
asked Nov 22 '18 at 11:57
elloello
154
154
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
Try this:
const newArray = [...JsonData["Phone"], ...JsonData["Computer"]];
const result = newArray.filter(item => {
if(item.temp.indexOf("4") !== -1) return item.name;
});
The result will be: ["iPhone", "Samsung"].
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
add a comment |
0
This code will help you to parse the JSON
function loopObj(value, array){
let keyList = Object.keys(array)
var namesArray =
for (var i = 0; i < keys.length; i++) {
let arrayVal = a[keys[i]];
for (var j = 0; j < arrayVal.length; j++) {
var innerArray = arrayVal[j]
if (innerArray.temp.indexOf(value) >= 0) {
namesArray.push(innerArray.name)
}
}
}
return(namesArray)
}
loopObj("4", a) // will give you the array ["iPhone", "Samsung"]
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Try this:
const newArray = [...JsonData["Phone"], ...JsonData["Computer"]];
const result = newArray.filter(item => {
if(item.temp.indexOf("4") !== -1) return item.name;
});
The result will be: ["iPhone", "Samsung"].
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
add a comment |
0
Try this:
const newArray = [...JsonData["Phone"], ...JsonData["Computer"]];
const result = newArray.filter(item => {
if(item.temp.indexOf("4") !== -1) return item.name;
});
The result will be: ["iPhone", "Samsung"].
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
add a comment |
0
0
0
Try this:
const newArray = [...JsonData["Phone"], ...JsonData["Computer"]];
const result = newArray.filter(item => {
if(item.temp.indexOf("4") !== -1) return item.name;
});
The result will be: ["iPhone", "Samsung"].
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
Try this:
const newArray = [...JsonData["Phone"], ...JsonData["Computer"]];
const result = newArray.filter(item => {
if(item.temp.indexOf("4") !== -1) return item.name;
});
The result will be: ["iPhone", "Samsung"].
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
answered Nov 22 '18 at 22:56
DiamantDiamant
10818
10818
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
add a comment |
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
Thank you! By the Way, I tried to print out the result like this, <Text style={styles.title}>{result}</Text> But ran into this error. "Invariant Violation: Objects are not valid as a React child(found:object with keys)". Do you know how to solve it?
– ello
Nov 23 '18 at 2:55
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
I solved it using the flat list!
– ello
Nov 23 '18 at 6:26
add a comment |
0
This code will help you to parse the JSON
function loopObj(value, array){
let keyList = Object.keys(array)
var namesArray =
for (var i = 0; i < keys.length; i++) {
let arrayVal = a[keys[i]];
for (var j = 0; j < arrayVal.length; j++) {
var innerArray = arrayVal[j]
if (innerArray.temp.indexOf(value) >= 0) {
namesArray.push(innerArray.name)
}
}
}
return(namesArray)
}
loopObj("4", a) // will give you the array ["iPhone", "Samsung"]
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
add a comment |
0
This code will help you to parse the JSON
function loopObj(value, array){
let keyList = Object.keys(array)
var namesArray =
for (var i = 0; i < keys.length; i++) {
let arrayVal = a[keys[i]];
for (var j = 0; j < arrayVal.length; j++) {
var innerArray = arrayVal[j]
if (innerArray.temp.indexOf(value) >= 0) {
namesArray.push(innerArray.name)
}
}
}
return(namesArray)
}
loopObj("4", a) // will give you the array ["iPhone", "Samsung"]
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
add a comment |
0
0
0
This code will help you to parse the JSON
function loopObj(value, array){
let keyList = Object.keys(array)
var namesArray =
for (var i = 0; i < keys.length; i++) {
let arrayVal = a[keys[i]];
for (var j = 0; j < arrayVal.length; j++) {
var innerArray = arrayVal[j]
if (innerArray.temp.indexOf(value) >= 0) {
namesArray.push(innerArray.name)
}
}
}
return(namesArray)
}
loopObj("4", a) // will give you the array ["iPhone", "Samsung"]
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
This code will help you to parse the JSON
function loopObj(value, array){
let keyList = Object.keys(array)
var namesArray =
for (var i = 0; i < keys.length; i++) {
let arrayVal = a[keys[i]];
for (var j = 0; j < arrayVal.length; j++) {
var innerArray = arrayVal[j]
if (innerArray.temp.indexOf(value) >= 0) {
namesArray.push(innerArray.name)
}
}
}
return(namesArray)
}
loopObj("4", a) // will give you the array ["iPhone", "Samsung"]
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
answered Nov 22 '18 at 13:21
Manju BashaManju Basha
312420
312420
add a comment |
add a comment |
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