Set the last number in a string to negative

-3

I have a string with diffrent mathematical characters, and i want to make the last number negative/positive. Let's say the string is "100/5*30-60+333". The result i want is "100/5*30-60+(-333)", and i want to convert it back to positive ("100/5*30-60+333").

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n.split('+');

  n.split('-');

  n.split('*');

  n.split('/');

  console.log(n);

}

What i get is the whole hiddenText.value, and not an array of all numbers. Any tips?

asked Jan 2 at 8:15

Elias Wennerlund

But... Why do you want to do that?

– Islam Elshobokshy
Jan 2 at 8:17

1

Would not that be essentially a non-op? I don't understand the converting back part; just keep the original.

– Drew Reese
Jan 2 at 8:24

add a comment |

-3

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n.split('+');

  n.split('-');

  n.split('*');

  n.split('/');

  console.log(n);

}

What i get is the whole hiddenText.value, and not an array of all numbers. Any tips?

asked Jan 2 at 8:15

Elias Wennerlund

But... Why do you want to do that?

– Islam Elshobokshy
Jan 2 at 8:17

1

Would not that be essentially a non-op? I don't understand the converting back part; just keep the original.

– Drew Reese
Jan 2 at 8:24

add a comment |

-3

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n.split('+');

  n.split('-');

  n.split('*');

  n.split('/');

  console.log(n);

}

What i get is the whole hiddenText.value, and not an array of all numbers. Any tips?

asked Jan 2 at 8:15

Elias Wennerlund

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n.split('+');

  n.split('-');

  n.split('*');

  n.split('/');

  console.log(n);

}

What i get is the whole hiddenText.value, and not an array of all numbers. Any tips?

javascript arrays string

asked Jan 2 at 8:15

Elias Wennerlund

asked Jan 2 at 8:15

Elias Wennerlund

asked Jan 2 at 8:15

Elias Wennerlund

asked Jan 2 at 8:15

Elias Wennerlund

asked Jan 2 at 8:15

Elias Wennerlund

But... Why do you want to do that?

– Islam Elshobokshy
Jan 2 at 8:17

1

Would not that be essentially a non-op? I don't understand the converting back part; just keep the original.

– Drew Reese
Jan 2 at 8:24

add a comment |

But... Why do you want to do that?

– Islam Elshobokshy
Jan 2 at 8:17

1

Would not that be essentially a non-op? I don't understand the converting back part; just keep the original.

– Drew Reese
Jan 2 at 8:24

But... Why do you want to do that?

– Islam Elshobokshy
Jan 2 at 8:17

Would not that be essentially a non-op? I don't understand the converting back part; just keep the original.

– Drew Reese
Jan 2 at 8:24

add a comment |

4 Answers
4

active

oldest

votes

Let's say the string is "100/5*30-60+333". The result i want is
"100/5*30-60+(-333)", and i want to convert it back to positive
("100/5*30-60+333").

The following code does that:

let mathStr = '100/5*30-60+333';

console.log(mathStr);

let tokens = mathStr.split('+');

let index = tokens.length - 1;

let lastToken = tokens[index];

lastToken = '('.concat('-', lastToken, ')');

let newMathStr = tokens[0].concat('+', lastToken);

console.log(newMathStr); // 100/5*30-60+(-333)

console.log(mathStr); // 100/5*30-60+333

EDIT:

... and i want to convert it back to positive ("100/5*30-60+333").

One way is to declare mathStr (with the value "100/5*30-60+333") as a var at the beginning and reuse it, later as you need. Another way is to code as follows:

let str = "100/5*30-60+(-333)";

str = str.replace('(-', '').replace(')', '');

console.log(str); // 100/5*30-60+333

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

add a comment |

First, I'd match all of the basic math operators to get their order:

const operatorsArr = n.match(/+|-|/|*/g)

Then, split the string:

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n = n.replace(/+|-|/|*/g, '|');

  n = n.split('|');

  console.log(n);

}

Then, you will have an array of numbers, in which you can mutate the last number easily:

n[n.lengh-1] *= -1;

Now we can combine the two arrays together:

let newArr;

for (let i = 0; i < n.length; i++) {

  newArr.push(n[i]);

  if (operatorsArr[i]) newArr.push(operatorsArr[i]);

}

At last, you can rejoin the array to create the new String with a seperator of your choosing. In this example I'm using a space:

newArr = newArr.join(' ')

Please let me know how that works out for you.

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

add a comment |

To get numbers You can use replace function and split check code bellow :

   function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = "100/5*30-60+333";

  n = n.replace('+','|+');

  n = n.replace('-','|-');

  n = n.replace('*','|*');

  n = n.replace('/','|/');

  n=n.split('|');console.log(n);

// to use any caracter from array use it in removeop like example 

// if we have array (split return) have 100 5 30 60 333 we get 100 for example 

// we need to make removeop(n[0]) and that reutrn 100;

// ok now to replace last value to negative in string you can just make 

// var lastv=n[n.length-1];

// n[n.length-1] ='(-'+n[n.length-1])+')';

//var newstring=n.join('');

//n[n.length-1]=lastv;

//var oldstring=n.join('');





}





function removeop(stringop)

{



  stringop = stringop.replace('+','');

  stringop = stringop.replace('-','');

  stringop = stringop.replace('*','');

  stringop = stringop.replace('/','');

return stringop;

}

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

add a comment |

If you really need to add "()", then you can modify accordingly

<script>

function myConversion(){

  var str = "100/5*30-60-333";

  var p = str.lastIndexOf("+");



  if(p>-1)

  {

  str = str.replaceAt(p,"-");

  }

  else

  {

  var n = str.lastIndexOf("-");

  if(n>-1)

  str = str.replaceAt(n,"+");

  }

  console.log(str);

}

String.prototype.replaceAt=function(index, replacement) {

    return this.substr(0, index) + replacement+ this.substr(index + replacement.length);  



}

</script>

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

add a comment |

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

Let's say the string is "100/5*30-60+333". The result i want is
"100/5*30-60+(-333)", and i want to convert it back to positive
("100/5*30-60+333").

The following code does that:

let mathStr = '100/5*30-60+333';

console.log(mathStr);

let tokens = mathStr.split('+');

let index = tokens.length - 1;

let lastToken = tokens[index];

lastToken = '('.concat('-', lastToken, ')');

let newMathStr = tokens[0].concat('+', lastToken);

console.log(newMathStr); // 100/5*30-60+(-333)

console.log(mathStr); // 100/5*30-60+333

EDIT:

... and i want to convert it back to positive ("100/5*30-60+333").

One way is to declare mathStr (with the value "100/5*30-60+333") as a var at the beginning and reuse it, later as you need. Another way is to code as follows:

let str = "100/5*30-60+(-333)";

str = str.replace('(-', '').replace(')', '');

console.log(str); // 100/5*30-60+333

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

add a comment |

Let's say the string is "100/5*30-60+333". The result i want is
"100/5*30-60+(-333)", and i want to convert it back to positive
("100/5*30-60+333").

The following code does that:

let mathStr = '100/5*30-60+333';

console.log(mathStr);

let tokens = mathStr.split('+');

let index = tokens.length - 1;

let lastToken = tokens[index];

lastToken = '('.concat('-', lastToken, ')');

let newMathStr = tokens[0].concat('+', lastToken);

console.log(newMathStr); // 100/5*30-60+(-333)

console.log(mathStr); // 100/5*30-60+333

EDIT:

... and i want to convert it back to positive ("100/5*30-60+333").

One way is to declare mathStr (with the value "100/5*30-60+333") as a var at the beginning and reuse it, later as you need. Another way is to code as follows:

let str = "100/5*30-60+(-333)";

str = str.replace('(-', '').replace(')', '');

console.log(str); // 100/5*30-60+333

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

add a comment |

Let's say the string is "100/5*30-60+333". The result i want is
"100/5*30-60+(-333)", and i want to convert it back to positive
("100/5*30-60+333").

The following code does that:

let mathStr = '100/5*30-60+333';

console.log(mathStr);

let tokens = mathStr.split('+');

let index = tokens.length - 1;

let lastToken = tokens[index];

lastToken = '('.concat('-', lastToken, ')');

let newMathStr = tokens[0].concat('+', lastToken);

console.log(newMathStr); // 100/5*30-60+(-333)

console.log(mathStr); // 100/5*30-60+333

EDIT:

... and i want to convert it back to positive ("100/5*30-60+333").

One way is to declare mathStr (with the value "100/5*30-60+333") as a var at the beginning and reuse it, later as you need. Another way is to code as follows:

let str = "100/5*30-60+(-333)";

str = str.replace('(-', '').replace(')', '');

console.log(str); // 100/5*30-60+333

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

Let's say the string is "100/5*30-60+333". The result i want is
"100/5*30-60+(-333)", and i want to convert it back to positive
("100/5*30-60+333").

The following code does that:

let mathStr = '100/5*30-60+333';

console.log(mathStr);

let tokens = mathStr.split('+');

let index = tokens.length - 1;

let lastToken = tokens[index];

lastToken = '('.concat('-', lastToken, ')');

let newMathStr = tokens[0].concat('+', lastToken);

console.log(newMathStr); // 100/5*30-60+(-333)

console.log(mathStr); // 100/5*30-60+333

EDIT:

... and i want to convert it back to positive ("100/5*30-60+333").

One way is to declare mathStr (with the value "100/5*30-60+333") as a var at the beginning and reuse it, later as you need. Another way is to code as follows:

let str = "100/5*30-60+(-333)";

str = str.replace('(-', '').replace(')', '');

console.log(str); // 100/5*30-60+333

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

edited Jan 2 at 12:46

answered Jan 2 at 9:28

prasad_

1,5681718

answered Jan 2 at 9:28

prasad_

1,5681718

answered Jan 2 at 9:28

prasad_

1,5681718

add a comment |

First, I'd match all of the basic math operators to get their order:

const operatorsArr = n.match(/+|-|/|*/g)

Then, split the string:

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n = n.replace(/+|-|/|*/g, '|');

  n = n.split('|');

  console.log(n);

}

Then, you will have an array of numbers, in which you can mutate the last number easily:

n[n.lengh-1] *= -1;

Now we can combine the two arrays together:

let newArr;

for (let i = 0; i < n.length; i++) {

  newArr.push(n[i]);

  if (operatorsArr[i]) newArr.push(operatorsArr[i]);

}

At last, you can rejoin the array to create the new String with a seperator of your choosing. In this example I'm using a space:

newArr = newArr.join(' ')

Please let me know how that works out for you.

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

add a comment |

First, I'd match all of the basic math operators to get their order:

const operatorsArr = n.match(/+|-|/|*/g)

Then, split the string:

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n = n.replace(/+|-|/|*/g, '|');

  n = n.split('|');

  console.log(n);

}

Then, you will have an array of numbers, in which you can mutate the last number easily:

n[n.lengh-1] *= -1;

Now we can combine the two arrays together:

let newArr;

for (let i = 0; i < n.length; i++) {

  newArr.push(n[i]);

  if (operatorsArr[i]) newArr.push(operatorsArr[i]);

}

At last, you can rejoin the array to create the new String with a seperator of your choosing. In this example I'm using a space:

newArr = newArr.join(' ')

Please let me know how that works out for you.

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

add a comment |

First, I'd match all of the basic math operators to get their order:

const operatorsArr = n.match(/+|-|/|*/g)

Then, split the string:

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n = n.replace(/+|-|/|*/g, '|');

  n = n.split('|');

  console.log(n);

}

Then, you will have an array of numbers, in which you can mutate the last number easily:

n[n.lengh-1] *= -1;

Now we can combine the two arrays together:

let newArr;

for (let i = 0; i < n.length; i++) {

  newArr.push(n[i]);

  if (operatorsArr[i]) newArr.push(operatorsArr[i]);

}

At last, you can rejoin the array to create the new String with a seperator of your choosing. In this example I'm using a space:

newArr = newArr.join(' ')

Please let me know how that works out for you.

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

First, I'd match all of the basic math operators to get their order:

const operatorsArr = n.match(/+|-|/|*/g)

Then, split the string:

function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = hiddenText.value;

  n = n.replace(/+|-|/|*/g, '|');

  n = n.split('|');

  console.log(n);

}

Then, you will have an array of numbers, in which you can mutate the last number easily:

n[n.lengh-1] *= -1;

Now we can combine the two arrays together:

let newArr;

for (let i = 0; i < n.length; i++) {

  newArr.push(n[i]);

  if (operatorsArr[i]) newArr.push(operatorsArr[i]);

}

At last, you can rejoin the array to create the new String with a seperator of your choosing. In this example I'm using a space:

newArr = newArr.join(' ')

Please let me know how that works out for you.

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

edited Jan 2 at 8:53

answered Jan 2 at 8:18

Sagi Rika

8611

answered Jan 2 at 8:18

Sagi Rika

8611

answered Jan 2 at 8:18

Sagi Rika

8611

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

add a comment |

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

I believe it is, since he said the problem is that the output of console.log is the full input value.

– Sagi Rika
Jan 2 at 8:20

Editted the answer, I believe it answers his question now.

– Sagi Rika
Jan 2 at 8:48

add a comment |

To get numbers You can use replace function and split check code bellow :

   function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = "100/5*30-60+333";

  n = n.replace('+','|+');

  n = n.replace('-','|-');

  n = n.replace('*','|*');

  n = n.replace('/','|/');

  n=n.split('|');console.log(n);

// to use any caracter from array use it in removeop like example 

// if we have array (split return) have 100 5 30 60 333 we get 100 for example 

// we need to make removeop(n[0]) and that reutrn 100;

// ok now to replace last value to negative in string you can just make 

// var lastv=n[n.length-1];

// n[n.length-1] ='(-'+n[n.length-1])+')';

//var newstring=n.join('');

//n[n.length-1]=lastv;

//var oldstring=n.join('');





}





function removeop(stringop)

{



  stringop = stringop.replace('+','');

  stringop = stringop.replace('-','');

  stringop = stringop.replace('*','');

  stringop = stringop.replace('/','');

return stringop;

}

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

add a comment |

To get numbers You can use replace function and split check code bellow :

   function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = "100/5*30-60+333";

  n = n.replace('+','|+');

  n = n.replace('-','|-');

  n = n.replace('*','|*');

  n = n.replace('/','|/');

  n=n.split('|');console.log(n);

// to use any caracter from array use it in removeop like example 

// if we have array (split return) have 100 5 30 60 333 we get 100 for example 

// we need to make removeop(n[0]) and that reutrn 100;

// ok now to replace last value to negative in string you can just make 

// var lastv=n[n.length-1];

// n[n.length-1] ='(-'+n[n.length-1])+')';

//var newstring=n.join('');

//n[n.length-1]=lastv;

//var oldstring=n.join('');





}





function removeop(stringop)

{



  stringop = stringop.replace('+','');

  stringop = stringop.replace('-','');

  stringop = stringop.replace('*','');

  stringop = stringop.replace('/','');

return stringop;

}

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

add a comment |

To get numbers You can use replace function and split check code bellow :

   function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = "100/5*30-60+333";

  n = n.replace('+','|+');

  n = n.replace('-','|-');

  n = n.replace('*','|*');

  n = n.replace('/','|/');

  n=n.split('|');console.log(n);

// to use any caracter from array use it in removeop like example 

// if we have array (split return) have 100 5 30 60 333 we get 100 for example 

// we need to make removeop(n[0]) and that reutrn 100;

// ok now to replace last value to negative in string you can just make 

// var lastv=n[n.length-1];

// n[n.length-1] ='(-'+n[n.length-1])+')';

//var newstring=n.join('');

//n[n.length-1]=lastv;

//var oldstring=n.join('');





}





function removeop(stringop)

{



  stringop = stringop.replace('+','');

  stringop = stringop.replace('-','');

  stringop = stringop.replace('*','');

  stringop = stringop.replace('/','');

return stringop;

}

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

To get numbers You can use replace function and split check code bellow :

   function posNeg() {

  // hiddenText is a <input> element. This is not shown.

  let n = "100/5*30-60+333";

  n = n.replace('+','|+');

  n = n.replace('-','|-');

  n = n.replace('*','|*');

  n = n.replace('/','|/');

  n=n.split('|');console.log(n);

// to use any caracter from array use it in removeop like example 

// if we have array (split return) have 100 5 30 60 333 we get 100 for example 

// we need to make removeop(n[0]) and that reutrn 100;

// ok now to replace last value to negative in string you can just make 

// var lastv=n[n.length-1];

// n[n.length-1] ='(-'+n[n.length-1])+')';

//var newstring=n.join('');

//n[n.length-1]=lastv;

//var oldstring=n.join('');





}





function removeop(stringop)

{



  stringop = stringop.replace('+','');

  stringop = stringop.replace('-','');

  stringop = stringop.replace('*','');

  stringop = stringop.replace('/','');

return stringop;

}

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

edited Jan 2 at 8:50

answered Jan 2 at 8:27

HamzaNig

810532

answered Jan 2 at 8:27

HamzaNig

810532

answered Jan 2 at 8:27

HamzaNig

810532

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

add a comment |

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

Once you've split it, how do you put it back together?

– Mark Meyer
Jan 2 at 8:31

i updated my code

– HamzaNig
Jan 2 at 8:50

add a comment |

If you really need to add "()", then you can modify accordingly

<script>

function myConversion(){

  var str = "100/5*30-60-333";

  var p = str.lastIndexOf("+");



  if(p>-1)

  {

  str = str.replaceAt(p,"-");

  }

  else

  {

  var n = str.lastIndexOf("-");

  if(n>-1)

  str = str.replaceAt(n,"+");

  }

  console.log(str);

}

String.prototype.replaceAt=function(index, replacement) {

    return this.substr(0, index) + replacement+ this.substr(index + replacement.length);  



}

</script>

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

add a comment |

If you really need to add "()", then you can modify accordingly

<script>

function myConversion(){

  var str = "100/5*30-60-333";

  var p = str.lastIndexOf("+");



  if(p>-1)

  {

  str = str.replaceAt(p,"-");

  }

  else

  {

  var n = str.lastIndexOf("-");

  if(n>-1)

  str = str.replaceAt(n,"+");

  }

  console.log(str);

}

String.prototype.replaceAt=function(index, replacement) {

    return this.substr(0, index) + replacement+ this.substr(index + replacement.length);  



}

</script>

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

add a comment |

If you really need to add "()", then you can modify accordingly

<script>

function myConversion(){

  var str = "100/5*30-60-333";

  var p = str.lastIndexOf("+");



  if(p>-1)

  {

  str = str.replaceAt(p,"-");

  }

  else

  {

  var n = str.lastIndexOf("-");

  if(n>-1)

  str = str.replaceAt(n,"+");

  }

  console.log(str);

}

String.prototype.replaceAt=function(index, replacement) {

    return this.substr(0, index) + replacement+ this.substr(index + replacement.length);  



}

</script>

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

If you really need to add "()", then you can modify accordingly

<script>

function myConversion(){

  var str = "100/5*30-60-333";

  var p = str.lastIndexOf("+");



  if(p>-1)

  {

  str = str.replaceAt(p,"-");

  }

  else

  {

  var n = str.lastIndexOf("-");

  if(n>-1)

  str = str.replaceAt(n,"+");

  }

  console.log(str);

}

String.prototype.replaceAt=function(index, replacement) {

    return this.substr(0, index) + replacement+ this.substr(index + replacement.length);  



}

</script>

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

edited Jan 2 at 9:12

answered Jan 2 at 9:07

Ud_Undefined

395

answered Jan 2 at 9:07

Ud_Undefined

395

answered Jan 2 at 9:07

Ud_Undefined

395

add a comment |

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