What times what equals something?
$begingroup$
I wanted to find x
times y
equals to z
, where z
can be anything (Full number).
What I wanted :
I can say, I want to find what x
times y
equals to 65
.
The answer is 13
times 5
.
Now, I wanted that 65
or z
to be anything.
I've found this site : https://researchmaniacs.com/Calculate/WhatTimesWhat/What-Times-What-Equals.html which does exactly that but unfortunately it only allows up to 5 digits number and the mechanics on how it works was not shown.
soft-question
$endgroup$
add a comment |
$begingroup$
I wanted to find x
times y
equals to z
, where z
can be anything (Full number).
What I wanted :
I can say, I want to find what x
times y
equals to 65
.
The answer is 13
times 5
.
Now, I wanted that 65
or z
to be anything.
I've found this site : https://researchmaniacs.com/Calculate/WhatTimesWhat/What-Times-What-Equals.html which does exactly that but unfortunately it only allows up to 5 digits number and the mechanics on how it works was not shown.
soft-question
$endgroup$
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05
add a comment |
$begingroup$
I wanted to find x
times y
equals to z
, where z
can be anything (Full number).
What I wanted :
I can say, I want to find what x
times y
equals to 65
.
The answer is 13
times 5
.
Now, I wanted that 65
or z
to be anything.
I've found this site : https://researchmaniacs.com/Calculate/WhatTimesWhat/What-Times-What-Equals.html which does exactly that but unfortunately it only allows up to 5 digits number and the mechanics on how it works was not shown.
soft-question
$endgroup$
I wanted to find x
times y
equals to z
, where z
can be anything (Full number).
What I wanted :
I can say, I want to find what x
times y
equals to 65
.
The answer is 13
times 5
.
Now, I wanted that 65
or z
to be anything.
I've found this site : https://researchmaniacs.com/Calculate/WhatTimesWhat/What-Times-What-Equals.html which does exactly that but unfortunately it only allows up to 5 digits number and the mechanics on how it works was not shown.
soft-question
soft-question
asked Jan 26 at 3:02


PlanetGamingGGPlanetGamingGG
6
6
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05
add a comment |
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087858%2fwhat-times-what-equals-something%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087858%2fwhat-times-what-equals-something%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
They just find all divisors of $z$. You can easily google an algorithm on how to do that
$endgroup$
– user635162
Jan 26 at 3:05