Mixing
How can I get the center coordinates of a rectangle in javafx?
-1
do anyone has an idea on how to get the center-coordinates of an rectangle in javafx?
Is there a method or an algorithm for that, couse I want to know the center-position while the rectangle is rotating and moving.
I couldn't find a solution on the web so I hope one of you can help me.
javafx
asked Jan 1 at 10:27
lukasQlukasQ
11
add a comment |
-1
do anyone has an idea on how to get the center-coordinates of an rectangle in javafx?
Is there a method or an algorithm for that, couse I want to know the center-position while the rectangle is rotating and moving.
I couldn't find a solution on the web so I hope one of you can help me.
javafx
asked Jan 1 at 10:27
lukasQlukasQ
11
add a comment |
-1
-1
-1
do anyone has an idea on how to get the center-coordinates of an rectangle in javafx?
Is there a method or an algorithm for that, couse I want to know the center-position while the rectangle is rotating and moving.
I couldn't find a solution on the web so I hope one of you can help me.
javafx
asked Jan 1 at 10:27
lukasQlukasQ
11
do anyone has an idea on how to get the center-coordinates of an rectangle in javafx?
Is there a method or an algorithm for that, couse I want to know the center-position while the rectangle is rotating and moving.
I couldn't find a solution on the web so I hope one of you can help me.
javafx
javafx
asked Jan 1 at 10:27
lukasQlukasQ
11
asked Jan 1 at 10:27
lukasQlukasQ
11
asked Jan 1 at 10:27
lukasQlukasQ
11
asked Jan 1 at 10:27
lukasQlukasQ
11
asked Jan 1 at 10:27
lukasQlukasQ
11
11
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
You can calculate the center of a rectangle like this:
center.x = position.x + width / 2
center.y = position.y + height / 2
Or if you represent your rectangle as 2 points (two opposite corners) you would have to use the following formula:
p0
+-------+
| |
| |
+-------+
p1
center.x = (p0.x + p1.x) / 2
center.y = (p0.y + p1.y) / 2
Also:
A quick google yields How to find the Center Coordinate of Rectangle? as first result...
answered Jan 1 at 10:48
KanjiuKanjiu
42110
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
Note you probably want to compute the center based on the rectangle'sboundsInParentproperty; then all transforms are taken into account.
– Slaw
Jan 1 at 12:26
|
show 3 more comments
1
Use the localToParent method to convert the center of the rectangle to the coordinate system of the parent.
The center of the Rectangle in local coordinates is
x = rect.x + rect.width/2
y = rect.y + rect.height/2
Example
@Override
public void start(Stage primaryStage) throws Exception {
Rectangle rect = new Rectangle(50, 50, 100, 100);
Translate translate = new Translate();
Rotate rotate = new Rotate(0, 0, 0);
rect.getTransforms().addAll(translate, rotate);
Circle circle = new Circle(5, Color.RED);
AnimationTimer timer = new AnimationTimer() {
@Override
public void handle(long now) {
double d = now / 5_000_000_000d;
rotate.setAngle(d * 360);
translate.setX((d % 2) * 300);
translate.setY((d % 3) * 150);
// set circle center to coordinates of rect's center
Point2D center = rect.localToParent(rect.getX() + 0.5 * rect.getWidth(),
rect.getY() + 0.5 * rect.getHeight());
circle.setCenterX(center.getX());
circle.setCenterY(center.getY());
}
};
Pane root = new Pane(rect, circle);
timer.start();
Scene scene = new Scene(root, 800, 800);
primaryStage.setScene(scene);
primaryStage.show();
}
answered Jan 1 at 12:33
fabianfabian
52.6k115373
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53994718%2fhow-can-i-get-the-center-coordinates-of-a-rectangle-in-javafx%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can calculate the center of a rectangle like this:
center.x = position.x + width / 2
center.y = position.y + height / 2
Or if you represent your rectangle as 2 points (two opposite corners) you would have to use the following formula:
p0
+-------+
| |
| |
+-------+
p1
center.x = (p0.x + p1.x) / 2
center.y = (p0.y + p1.y) / 2
Also:
A quick google yields How to find the Center Coordinate of Rectangle? as first result...
answered Jan 1 at 10:48
KanjiuKanjiu
42110
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
Note you probably want to compute the center based on the rectangle'sboundsInParentproperty; then all transforms are taken into account.
– Slaw
Jan 1 at 12:26
|
show 3 more comments
1
You can calculate the center of a rectangle like this:
center.x = position.x + width / 2
center.y = position.y + height / 2
Or if you represent your rectangle as 2 points (two opposite corners) you would have to use the following formula:
p0
+-------+
| |
| |
+-------+
p1
center.x = (p0.x + p1.x) / 2
center.y = (p0.y + p1.y) / 2
Also:
A quick google yields How to find the Center Coordinate of Rectangle? as first result...
answered Jan 1 at 10:48
KanjiuKanjiu
42110
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
Note you probably want to compute the center based on the rectangle'sboundsInParentproperty; then all transforms are taken into account.
– Slaw
Jan 1 at 12:26
|
show 3 more comments
1
1
1
You can calculate the center of a rectangle like this:
center.x = position.x + width / 2
center.y = position.y + height / 2
Or if you represent your rectangle as 2 points (two opposite corners) you would have to use the following formula:
p0
+-------+
| |
| |
+-------+
p1
center.x = (p0.x + p1.x) / 2
center.y = (p0.y + p1.y) / 2
Also:
A quick google yields How to find the Center Coordinate of Rectangle? as first result...
answered Jan 1 at 10:48
KanjiuKanjiu
42110
You can calculate the center of a rectangle like this:
center.x = position.x + width / 2
center.y = position.y + height / 2
Or if you represent your rectangle as 2 points (two opposite corners) you would have to use the following formula:
p0
+-------+
| |
| |
+-------+
p1
center.x = (p0.x + p1.x) / 2
center.y = (p0.y + p1.y) / 2
Also:
A quick google yields How to find the Center Coordinate of Rectangle? as first result...
answered Jan 1 at 10:48
KanjiuKanjiu
42110
edited Jan 1 at 11:06
answered Jan 1 at 10:48
KanjiuKanjiu
42110
answered Jan 1 at 10:48
KanjiuKanjiu
42110
answered Jan 1 at 10:48
KanjiuKanjiu
42110
42110
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
Note you probably want to compute the center based on the rectangle'sboundsInParentproperty; then all transforms are taken into account.
– Slaw
Jan 1 at 12:26
|
show 3 more comments
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
Note you probably want to compute the center based on the rectangle'sboundsInParentproperty; then all transforms are taken into account.
– Slaw
Jan 1 at 12:26
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
thanks for your answer but I think this method is useless while the rectangle is rotating, isn't it?
– lukasQ
Jan 1 at 11:00
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
It works perfectly fine for a rotated rectangle. Imagine drawing a diagonal line through your rectangle and then marking the center of this line. It will also work on a scaled, translated and sheared rectangle.
– Kanjiu
Jan 1 at 11:08
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Wait... do you know the rotated points? Or is that your problem?
– Kanjiu
Jan 1 at 11:14
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
Sorry I am a beginner. How do one keep track of these opposite points? As far as I know the methods .getTranslatex() / .getTranslateY() always takes the most left and the uppest corner of the rectangle.
– lukasQ
Jan 1 at 11:21
1
1
Note you probably want to compute the center based on the rectangle's
boundsInParent property; then all transforms are taken into account.– Slaw
Jan 1 at 12:26
Note you probably want to compute the center based on the rectangle's
boundsInParent property; then all transforms are taken into account.– Slaw
Jan 1 at 12:26
|
show 3 more comments
1
Use the localToParent method to convert the center of the rectangle to the coordinate system of the parent.
The center of the Rectangle in local coordinates is
x = rect.x + rect.width/2
y = rect.y + rect.height/2
Example
@Override
public void start(Stage primaryStage) throws Exception {
Rectangle rect = new Rectangle(50, 50, 100, 100);
Translate translate = new Translate();
Rotate rotate = new Rotate(0, 0, 0);
rect.getTransforms().addAll(translate, rotate);
Circle circle = new Circle(5, Color.RED);
AnimationTimer timer = new AnimationTimer() {
@Override
public void handle(long now) {
double d = now / 5_000_000_000d;
rotate.setAngle(d * 360);
translate.setX((d % 2) * 300);
translate.setY((d % 3) * 150);
// set circle center to coordinates of rect's center
Point2D center = rect.localToParent(rect.getX() + 0.5 * rect.getWidth(),
rect.getY() + 0.5 * rect.getHeight());
circle.setCenterX(center.getX());
circle.setCenterY(center.getY());
}
};
Pane root = new Pane(rect, circle);
timer.start();
Scene scene = new Scene(root, 800, 800);
primaryStage.setScene(scene);
primaryStage.show();
}
answered Jan 1 at 12:33
fabianfabian
52.6k115373
add a comment |
1
Use the localToParent method to convert the center of the rectangle to the coordinate system of the parent.
The center of the Rectangle in local coordinates is
x = rect.x + rect.width/2
y = rect.y + rect.height/2
Example
@Override
public void start(Stage primaryStage) throws Exception {
Rectangle rect = new Rectangle(50, 50, 100, 100);
Translate translate = new Translate();
Rotate rotate = new Rotate(0, 0, 0);
rect.getTransforms().addAll(translate, rotate);
Circle circle = new Circle(5, Color.RED);
AnimationTimer timer = new AnimationTimer() {
@Override
public void handle(long now) {
double d = now / 5_000_000_000d;
rotate.setAngle(d * 360);
translate.setX((d % 2) * 300);
translate.setY((d % 3) * 150);
// set circle center to coordinates of rect's center
Point2D center = rect.localToParent(rect.getX() + 0.5 * rect.getWidth(),
rect.getY() + 0.5 * rect.getHeight());
circle.setCenterX(center.getX());
circle.setCenterY(center.getY());
}
};
Pane root = new Pane(rect, circle);
timer.start();
Scene scene = new Scene(root, 800, 800);
primaryStage.setScene(scene);
primaryStage.show();
}
answered Jan 1 at 12:33
fabianfabian
52.6k115373
add a comment |
1
1
1
Use the localToParent method to convert the center of the rectangle to the coordinate system of the parent.
The center of the Rectangle in local coordinates is
x = rect.x + rect.width/2
y = rect.y + rect.height/2
Example
@Override
public void start(Stage primaryStage) throws Exception {
Rectangle rect = new Rectangle(50, 50, 100, 100);
Translate translate = new Translate();
Rotate rotate = new Rotate(0, 0, 0);
rect.getTransforms().addAll(translate, rotate);
Circle circle = new Circle(5, Color.RED);
AnimationTimer timer = new AnimationTimer() {
@Override
public void handle(long now) {
double d = now / 5_000_000_000d;
rotate.setAngle(d * 360);
translate.setX((d % 2) * 300);
translate.setY((d % 3) * 150);
// set circle center to coordinates of rect's center
Point2D center = rect.localToParent(rect.getX() + 0.5 * rect.getWidth(),
rect.getY() + 0.5 * rect.getHeight());
circle.setCenterX(center.getX());
circle.setCenterY(center.getY());
}
};
Pane root = new Pane(rect, circle);
timer.start();
Scene scene = new Scene(root, 800, 800);
primaryStage.setScene(scene);
primaryStage.show();
}
answered Jan 1 at 12:33
fabianfabian
52.6k115373
Use the localToParent method to convert the center of the rectangle to the coordinate system of the parent.
The center of the Rectangle in local coordinates is
x = rect.x + rect.width/2
y = rect.y + rect.height/2
Example
@Override
public void start(Stage primaryStage) throws Exception {
Rectangle rect = new Rectangle(50, 50, 100, 100);
Translate translate = new Translate();
Rotate rotate = new Rotate(0, 0, 0);
rect.getTransforms().addAll(translate, rotate);
Circle circle = new Circle(5, Color.RED);
AnimationTimer timer = new AnimationTimer() {
@Override
public void handle(long now) {
double d = now / 5_000_000_000d;
rotate.setAngle(d * 360);
translate.setX((d % 2) * 300);
translate.setY((d % 3) * 150);
// set circle center to coordinates of rect's center
Point2D center = rect.localToParent(rect.getX() + 0.5 * rect.getWidth(),
rect.getY() + 0.5 * rect.getHeight());
circle.setCenterX(center.getX());
circle.setCenterY(center.getY());
}
};
Pane root = new Pane(rect, circle);
timer.start();
Scene scene = new Scene(root, 800, 800);
primaryStage.setScene(scene);
primaryStage.show();
}
answered Jan 1 at 12:33
fabianfabian
52.6k115373
answered Jan 1 at 12:33
fabianfabian
52.6k115373
answered Jan 1 at 12:33
fabianfabian
52.6k115373
answered Jan 1 at 12:33
fabianfabian
52.6k115373
52.6k115373
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53994718%2fhow-can-i-get-the-center-coordinates-of-a-rectangle-in-javafx%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
