Mixing
Finding the coefficients of a quadratic equation giving one point and open interval
-1
$begingroup$
Here is my question
The quadratic function f is negative only on the open interval (−2, 1/4 ) and its graph passes through the point (−1, −5). Determine the coefficients of f and sketch its graph.
please explain how you got your answer and thank you.
polynomials
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
$endgroup$
add a comment |
-1
$begingroup$
Here is my question
The quadratic function f is negative only on the open interval (−2, 1/4 ) and its graph passes through the point (−1, −5). Determine the coefficients of f and sketch its graph.
please explain how you got your answer and thank you.
polynomials
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
$endgroup$
add a comment |
-1
-1
-1
$begingroup$
Here is my question
The quadratic function f is negative only on the open interval (−2, 1/4 ) and its graph passes through the point (−1, −5). Determine the coefficients of f and sketch its graph.
please explain how you got your answer and thank you.
polynomials
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
$endgroup$
Here is my question
The quadratic function f is negative only on the open interval (−2, 1/4 ) and its graph passes through the point (−1, −5). Determine the coefficients of f and sketch its graph.
please explain how you got your answer and thank you.
polynomials
polynomials
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
asked Feb 2 at 21:30
Dylan OngDylan Ong
32
32
add a comment |
add a comment |
1 Answer
1
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$begingroup$
$f(x)=kappa(x+2)(x-frac{1}{4})$ then $f(-1)=-5$ to deduce $kappa$
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
$endgroup$
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
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active
oldest
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active
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votes
2
$begingroup$
$f(x)=kappa(x+2)(x-frac{1}{4})$ then $f(-1)=-5$ to deduce $kappa$
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
$endgroup$
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
add a comment |
2
$begingroup$
$f(x)=kappa(x+2)(x-frac{1}{4})$ then $f(-1)=-5$ to deduce $kappa$
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
$endgroup$
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
add a comment |
2
2
2
$begingroup$
$f(x)=kappa(x+2)(x-frac{1}{4})$ then $f(-1)=-5$ to deduce $kappa$
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
$endgroup$
$f(x)=kappa(x+2)(x-frac{1}{4})$ then $f(-1)=-5$ to deduce $kappa$
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
answered Feb 2 at 21:33
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,268212
2,268212
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
add a comment |
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
Please explain what the question means. Can you please provide more detail? Also, I need to know all 3 coefficients, not just one.Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:41
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
$f$ is quadratic and change sign at $-2$ and $frac{1}{4}$ therefore the two values are roots of $f$ and the claim follows.
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:46
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
I am a beginner. Please explain more. Thanks
$endgroup$
– Dylan Ong
Feb 2 at 21:49
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Look, can you trip from Los Angeles to Paris without crossing water? Los Angeles is the positive sign, Paris the negative and water is the « zero ». Since your function is positive before -2 and negative after -2, so $f(-2)=0$, hence it must be a (x-(-2)) as a factor of f. Same argument at 1/4. You must know that every quadratic function can be written as a(x-root1)(x-root2).
$endgroup$
– HAMIDINE SOUMARE
Feb 2 at 21:59
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
$begingroup$
Thank you for your explanation. I still wonder how I can get the other two.
$endgroup$
– Dylan Ong
Feb 2 at 22:21
add a comment |
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