Mixing
Solving System on Inequalities Numerically
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I am stuck on a problem that says given for the range [750,1800] (where each element has a spacing of 5 units: [750,755,760,...,1795,1800]), to select 4 elements from this range who are all at least 150 units apart from each other. I don’t need all possible solutions just a decent sample of possible solutions.
The only way I could think to do this was through some numerical/iterative approach in R or MATLAB, but I’m hoping that would be unnecessary and am looking for some suggestions.
Thank you.
inequality systems-of-equations
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
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add a comment |
$begingroup$
I am stuck on a problem that says given for the range [750,1800] (where each element has a spacing of 5 units: [750,755,760,...,1795,1800]), to select 4 elements from this range who are all at least 150 units apart from each other. I don’t need all possible solutions just a decent sample of possible solutions.
The only way I could think to do this was through some numerical/iterative approach in R or MATLAB, but I’m hoping that would be unnecessary and am looking for some suggestions.
Thank you.
inequality systems-of-equations
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
$endgroup$
add a comment |
$begingroup$
I am stuck on a problem that says given for the range [750,1800] (where each element has a spacing of 5 units: [750,755,760,...,1795,1800]), to select 4 elements from this range who are all at least 150 units apart from each other. I don’t need all possible solutions just a decent sample of possible solutions.
The only way I could think to do this was through some numerical/iterative approach in R or MATLAB, but I’m hoping that would be unnecessary and am looking for some suggestions.
Thank you.
inequality systems-of-equations
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
$endgroup$
I am stuck on a problem that says given for the range [750,1800] (where each element has a spacing of 5 units: [750,755,760,...,1795,1800]), to select 4 elements from this range who are all at least 150 units apart from each other. I don’t need all possible solutions just a decent sample of possible solutions.
The only way I could think to do this was through some numerical/iterative approach in R or MATLAB, but I’m hoping that would be unnecessary and am looking for some suggestions.
Thank you.
inequality systems-of-equations
inequality systems-of-equations
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
asked Feb 2 at 19:18
Thomas MooreThomas Moore
435510
435510
add a comment |
add a comment |
1 Answer
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Let one value be $750$, then select $750+150=900$, $900+150=1050$ and $1050+150=1200$. In fact we can pick any starting value up to $1350$ and perform the same procedure to get a valid sample. We can also pick elements spaced at different lengths away from each other such as $155,160,...$ to get even more valid samples.
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
votes
active
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votes
$begingroup$
Let one value be $750$, then select $750+150=900$, $900+150=1050$ and $1050+150=1200$. In fact we can pick any starting value up to $1350$ and perform the same procedure to get a valid sample. We can also pick elements spaced at different lengths away from each other such as $155,160,...$ to get even more valid samples.
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
$endgroup$
add a comment |
$begingroup$
Let one value be $750$, then select $750+150=900$, $900+150=1050$ and $1050+150=1200$. In fact we can pick any starting value up to $1350$ and perform the same procedure to get a valid sample. We can also pick elements spaced at different lengths away from each other such as $155,160,...$ to get even more valid samples.
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
$endgroup$
add a comment |
$begingroup$
Let one value be $750$, then select $750+150=900$, $900+150=1050$ and $1050+150=1200$. In fact we can pick any starting value up to $1350$ and perform the same procedure to get a valid sample. We can also pick elements spaced at different lengths away from each other such as $155,160,...$ to get even more valid samples.
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
$endgroup$
Let one value be $750$, then select $750+150=900$, $900+150=1050$ and $1050+150=1200$. In fact we can pick any starting value up to $1350$ and perform the same procedure to get a valid sample. We can also pick elements spaced at different lengths away from each other such as $155,160,...$ to get even more valid samples.
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
answered Feb 2 at 19:22
Peter ForemanPeter Foreman
7,2711319
7,2711319
add a comment |
add a comment |
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