How can I change the functions in the top and bottom of a double integral?












0












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How can I go from an integral looking like this:
$int_{0}^{2}int_{frac{y}{2}}^{1} f(x,y) dxdy $



To an integral looking like this:
$int_{0}^{1}int_{0}^{2x} f(x,y) dxdy $



I just want to know what the process is behind it and how we can change the integrals around?










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    0












    $begingroup$


    How can I go from an integral looking like this:
    $int_{0}^{2}int_{frac{y}{2}}^{1} f(x,y) dxdy $



    To an integral looking like this:
    $int_{0}^{1}int_{0}^{2x} f(x,y) dxdy $



    I just want to know what the process is behind it and how we can change the integrals around?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      How can I go from an integral looking like this:
      $int_{0}^{2}int_{frac{y}{2}}^{1} f(x,y) dxdy $



      To an integral looking like this:
      $int_{0}^{1}int_{0}^{2x} f(x,y) dxdy $



      I just want to know what the process is behind it and how we can change the integrals around?










      share|cite|improve this question









      $endgroup$




      How can I go from an integral looking like this:
      $int_{0}^{2}int_{frac{y}{2}}^{1} f(x,y) dxdy $



      To an integral looking like this:
      $int_{0}^{1}int_{0}^{2x} f(x,y) dxdy $



      I just want to know what the process is behind it and how we can change the integrals around?







      calculus






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 27 at 1:50









      George HarrisonGeorge Harrison

      82210




      82210






















          1 Answer
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          $begingroup$

          To reverse the order of integration you need to think about the area your integral is being calculated on. It goes from $x$ is $dfrac y2$ to $1$ and $y$ from $0$ to $2$. Sketch these two curves to visualize it.



          You should consider the range of $y$ values and then try to express the range of $x$ values as a function of $y$.



          Then you get $int_0^1int_0^{2x}f(x,y)dxdy$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
            $endgroup$
            – Key Flex
            Feb 17 at 21:57











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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          To reverse the order of integration you need to think about the area your integral is being calculated on. It goes from $x$ is $dfrac y2$ to $1$ and $y$ from $0$ to $2$. Sketch these two curves to visualize it.



          You should consider the range of $y$ values and then try to express the range of $x$ values as a function of $y$.



          Then you get $int_0^1int_0^{2x}f(x,y)dxdy$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
            $endgroup$
            – Key Flex
            Feb 17 at 21:57
















          0












          $begingroup$

          To reverse the order of integration you need to think about the area your integral is being calculated on. It goes from $x$ is $dfrac y2$ to $1$ and $y$ from $0$ to $2$. Sketch these two curves to visualize it.



          You should consider the range of $y$ values and then try to express the range of $x$ values as a function of $y$.



          Then you get $int_0^1int_0^{2x}f(x,y)dxdy$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
            $endgroup$
            – Key Flex
            Feb 17 at 21:57














          0












          0








          0





          $begingroup$

          To reverse the order of integration you need to think about the area your integral is being calculated on. It goes from $x$ is $dfrac y2$ to $1$ and $y$ from $0$ to $2$. Sketch these two curves to visualize it.



          You should consider the range of $y$ values and then try to express the range of $x$ values as a function of $y$.



          Then you get $int_0^1int_0^{2x}f(x,y)dxdy$






          share|cite|improve this answer









          $endgroup$



          To reverse the order of integration you need to think about the area your integral is being calculated on. It goes from $x$ is $dfrac y2$ to $1$ and $y$ from $0$ to $2$. Sketch these two curves to visualize it.



          You should consider the range of $y$ values and then try to express the range of $x$ values as a function of $y$.



          Then you get $int_0^1int_0^{2x}f(x,y)dxdy$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 27 at 2:06









          Key FlexKey Flex

          8,63561233




          8,63561233












          • $begingroup$
            @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
            $endgroup$
            – Key Flex
            Feb 17 at 21:57


















          • $begingroup$
            @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
            $endgroup$
            – Key Flex
            Feb 17 at 21:57
















          $begingroup$
          @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
          $endgroup$
          – Key Flex
          Feb 17 at 21:57




          $begingroup$
          @George Harrison If you find my answer helpful then accept the answer $checkmark$ :)
          $endgroup$
          – Key Flex
          Feb 17 at 21:57


















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