Mixing
How to do reduce rows with Wolfram Alpha over certain set
$begingroup$
If I want to row reduce a matrix:
$$
begin{matrix}
1 & -1 & 0 & 4 \
2 & -2 & 1 & 3 \
5 & -5 & 1 & 15 \
end{matrix}
$$
over $$mathbb{Z}_3$$ is there a way I can do this in Wolfram Alpha? Thanks!
matrices wolfram-alpha
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
$endgroup$
add a comment |
$begingroup$
If I want to row reduce a matrix:
$$
begin{matrix}
1 & -1 & 0 & 4 \
2 & -2 & 1 & 3 \
5 & -5 & 1 & 15 \
end{matrix}
$$
over $$mathbb{Z}_3$$ is there a way I can do this in Wolfram Alpha? Thanks!
matrices wolfram-alpha
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
$endgroup$
$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55
add a comment |
$begingroup$
If I want to row reduce a matrix:
$$
begin{matrix}
1 & -1 & 0 & 4 \
2 & -2 & 1 & 3 \
5 & -5 & 1 & 15 \
end{matrix}
$$
over $$mathbb{Z}_3$$ is there a way I can do this in Wolfram Alpha? Thanks!
matrices wolfram-alpha
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
$endgroup$
If I want to row reduce a matrix:
$$
begin{matrix}
1 & -1 & 0 & 4 \
2 & -2 & 1 & 3 \
5 & -5 & 1 & 15 \
end{matrix}
$$
over $$mathbb{Z}_3$$ is there a way I can do this in Wolfram Alpha? Thanks!
matrices wolfram-alpha
matrices wolfram-alpha
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
asked Sep 8 '14 at 0:33
user1282637user1282637
1817
1817
$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55
add a comment |
$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55
$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Use the syntax I have written here, then reduce mod 3 manually.
I just typed:
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}}]
As Amzoti points out well, and I just found out through test, WA just kinda burps on adding the Modulus->3 parameter.
Go to Wolfram Cloud, sign in to the "Wolfram Programming Cloud", and have your way with the Mathematica syntax. If you do it there, the statement
MatrixForm[
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}},
Modulus -> 3]]
will give you that which you desire with no cost. :)
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
$endgroup$
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Use the syntax I have written here, then reduce mod 3 manually.
I just typed:
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}}]
As Amzoti points out well, and I just found out through test, WA just kinda burps on adding the Modulus->3 parameter.
Go to Wolfram Cloud, sign in to the "Wolfram Programming Cloud", and have your way with the Mathematica syntax. If you do it there, the statement
MatrixForm[
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}},
Modulus -> 3]]
will give you that which you desire with no cost. :)
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
$endgroup$
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
add a comment |
$begingroup$
Use the syntax I have written here, then reduce mod 3 manually.
I just typed:
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}}]
As Amzoti points out well, and I just found out through test, WA just kinda burps on adding the Modulus->3 parameter.
Go to Wolfram Cloud, sign in to the "Wolfram Programming Cloud", and have your way with the Mathematica syntax. If you do it there, the statement
MatrixForm[
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}},
Modulus -> 3]]
will give you that which you desire with no cost. :)
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
$endgroup$
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
add a comment |
$begingroup$
Use the syntax I have written here, then reduce mod 3 manually.
I just typed:
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}}]
As Amzoti points out well, and I just found out through test, WA just kinda burps on adding the Modulus->3 parameter.
Go to Wolfram Cloud, sign in to the "Wolfram Programming Cloud", and have your way with the Mathematica syntax. If you do it there, the statement
MatrixForm[
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}},
Modulus -> 3]]
will give you that which you desire with no cost. :)
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
$endgroup$
Use the syntax I have written here, then reduce mod 3 manually.
I just typed:
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}}]
As Amzoti points out well, and I just found out through test, WA just kinda burps on adding the Modulus->3 parameter.
Go to Wolfram Cloud, sign in to the "Wolfram Programming Cloud", and have your way with the Mathematica syntax. If you do it there, the statement
MatrixForm[
RowReduce[{{1, -1, 0, 4}, {2, -2, 1, 3}, {5, -5, 1, 15}},
Modulus -> 3]]
will give you that which you desire with no cost. :)
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
edited Sep 8 '14 at 0:59
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
answered Sep 8 '14 at 0:51
J. W. PerryJ. W. Perry
4,83331724
4,83331724
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
add a comment |
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
$begingroup$
By "no cost", I mean basic Wolfram Programming Cloud accounts are free, and so get one. It is the solution, and a beautiful thing. What you can do with a free account might possibly split your brain. I am wondering if anyone outside of the Wolfram fan base knows this.
$endgroup$
– J. W. Perry
Sep 8 '14 at 1:16
add a comment |
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$begingroup$
@Amzoti very true, that's what I've been doing. Just wondering if there was an easier way
$endgroup$
– user1282637
Sep 8 '14 at 0:51
$begingroup$
cool, thanks for the help
$endgroup$
– user1282637
Sep 8 '14 at 0:55