Average Runtime of this code
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I was working on a problem to find the average case of a for loop that has a 1 step in it. Each element in the input array has a distribution of {0...i} where i is the index of the element.
What threw me off was that, in the for loop there is an if statement that would prematurely end the for loop and this "if statement" would be executed if the value of the array was 50.
The Psuedocode looks somewhat like this:
for i from 0 to n-1:
do something
if L[i] == 50:
do something, and break
and the input of the array are distributed like this:
L[0] = {0}
L[1] = {0, 1}
L[2] = {0, 1, 2}
L[i] = {0, 1, 2, .., i}
With duplicates being allowed and they're independent.
I already realized that there really was no need to look at the summation before index 50 of the array. Further more, the probability of not getting the value of the array was quite obviously i/i+1, however with this being said I do not know how to fully use the expected value theorem to get the expected running time of the program.
I would just like a little tip to get me on track. I feel like im really close to solving this but yet so far, thank you
real-analysis computational-complexity expected-value
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add a comment |
$begingroup$
I was working on a problem to find the average case of a for loop that has a 1 step in it. Each element in the input array has a distribution of {0...i} where i is the index of the element.
What threw me off was that, in the for loop there is an if statement that would prematurely end the for loop and this "if statement" would be executed if the value of the array was 50.
The Psuedocode looks somewhat like this:
for i from 0 to n-1:
do something
if L[i] == 50:
do something, and break
and the input of the array are distributed like this:
L[0] = {0}
L[1] = {0, 1}
L[2] = {0, 1, 2}
L[i] = {0, 1, 2, .., i}
With duplicates being allowed and they're independent.
I already realized that there really was no need to look at the summation before index 50 of the array. Further more, the probability of not getting the value of the array was quite obviously i/i+1, however with this being said I do not know how to fully use the expected value theorem to get the expected running time of the program.
I would just like a little tip to get me on track. I feel like im really close to solving this but yet so far, thank you
real-analysis computational-complexity expected-value
$endgroup$
add a comment |
$begingroup$
I was working on a problem to find the average case of a for loop that has a 1 step in it. Each element in the input array has a distribution of {0...i} where i is the index of the element.
What threw me off was that, in the for loop there is an if statement that would prematurely end the for loop and this "if statement" would be executed if the value of the array was 50.
The Psuedocode looks somewhat like this:
for i from 0 to n-1:
do something
if L[i] == 50:
do something, and break
and the input of the array are distributed like this:
L[0] = {0}
L[1] = {0, 1}
L[2] = {0, 1, 2}
L[i] = {0, 1, 2, .., i}
With duplicates being allowed and they're independent.
I already realized that there really was no need to look at the summation before index 50 of the array. Further more, the probability of not getting the value of the array was quite obviously i/i+1, however with this being said I do not know how to fully use the expected value theorem to get the expected running time of the program.
I would just like a little tip to get me on track. I feel like im really close to solving this but yet so far, thank you
real-analysis computational-complexity expected-value
$endgroup$
I was working on a problem to find the average case of a for loop that has a 1 step in it. Each element in the input array has a distribution of {0...i} where i is the index of the element.
What threw me off was that, in the for loop there is an if statement that would prematurely end the for loop and this "if statement" would be executed if the value of the array was 50.
The Psuedocode looks somewhat like this:
for i from 0 to n-1:
do something
if L[i] == 50:
do something, and break
and the input of the array are distributed like this:
L[0] = {0}
L[1] = {0, 1}
L[2] = {0, 1, 2}
L[i] = {0, 1, 2, .., i}
With duplicates being allowed and they're independent.
I already realized that there really was no need to look at the summation before index 50 of the array. Further more, the probability of not getting the value of the array was quite obviously i/i+1, however with this being said I do not know how to fully use the expected value theorem to get the expected running time of the program.
I would just like a little tip to get me on track. I feel like im really close to solving this but yet so far, thank you
real-analysis computational-complexity expected-value
real-analysis computational-complexity expected-value
asked Jan 28 at 21:20


Ace GokuAce Goku
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