What are the possible remainders when the $110^{th}$ power of an integer is divided by $121$? [duplicate]












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  • How do I compute $a^b,bmod c$ by hand?

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I was checking the following Euler's theorem exercise:




What are the possible remainders when the $110^{th}$ power of an integer is divided by $121$?




I've started working from calculating $phi (110) = 40$



Now I'm thinking about applying $mod 121$ but I'm unable to. So now I'm maybe in the wrong way. Any help or clue will be really appreciated.










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marked as duplicate by Jyrki Lahtonen, Bill Dubuque elementary-number-theory
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Feb 9 at 1:37


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














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    $begingroup$
    "I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
    $endgroup$
    – fleablood
    Jan 29 at 5:17








  • 1




    $begingroup$
    Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
    $endgroup$
    – Jyrki Lahtonen
    Jan 29 at 5:26


















1












$begingroup$



This question already has an answer here:




  • How do I compute $a^b,bmod c$ by hand?

    9 answers




I was checking the following Euler's theorem exercise:




What are the possible remainders when the $110^{th}$ power of an integer is divided by $121$?




I've started working from calculating $phi (110) = 40$



Now I'm thinking about applying $mod 121$ but I'm unable to. So now I'm maybe in the wrong way. Any help or clue will be really appreciated.










share|cite|improve this question











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marked as duplicate by Jyrki Lahtonen, Bill Dubuque elementary-number-theory
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Feb 9 at 1:37


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • 1




    $begingroup$
    "I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
    $endgroup$
    – fleablood
    Jan 29 at 5:17








  • 1




    $begingroup$
    Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
    $endgroup$
    – Jyrki Lahtonen
    Jan 29 at 5:26
















1












1








1





$begingroup$



This question already has an answer here:




  • How do I compute $a^b,bmod c$ by hand?

    9 answers




I was checking the following Euler's theorem exercise:




What are the possible remainders when the $110^{th}$ power of an integer is divided by $121$?




I've started working from calculating $phi (110) = 40$



Now I'm thinking about applying $mod 121$ but I'm unable to. So now I'm maybe in the wrong way. Any help or clue will be really appreciated.










share|cite|improve this question











$endgroup$





This question already has an answer here:




  • How do I compute $a^b,bmod c$ by hand?

    9 answers




I was checking the following Euler's theorem exercise:




What are the possible remainders when the $110^{th}$ power of an integer is divided by $121$?




I've started working from calculating $phi (110) = 40$



Now I'm thinking about applying $mod 121$ but I'm unable to. So now I'm maybe in the wrong way. Any help or clue will be really appreciated.





This question already has an answer here:




  • How do I compute $a^b,bmod c$ by hand?

    9 answers








elementary-number-theory modular-arithmetic






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edited Jan 29 at 5:14









Jyrki Lahtonen

110k13172387




110k13172387










asked Jan 29 at 4:49









mrazmraz

44319




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marked as duplicate by Jyrki Lahtonen, Bill Dubuque elementary-number-theory
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Feb 9 at 1:37


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









marked as duplicate by Jyrki Lahtonen, Bill Dubuque elementary-number-theory
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Feb 9 at 1:37


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.










  • 1




    $begingroup$
    "I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
    $endgroup$
    – fleablood
    Jan 29 at 5:17








  • 1




    $begingroup$
    Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
    $endgroup$
    – Jyrki Lahtonen
    Jan 29 at 5:26
















  • 1




    $begingroup$
    "I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
    $endgroup$
    – fleablood
    Jan 29 at 5:17








  • 1




    $begingroup$
    Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
    $endgroup$
    – Jyrki Lahtonen
    Jan 29 at 5:26










1




1




$begingroup$
"I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
$endgroup$
– fleablood
Jan 29 at 5:17






$begingroup$
"I've started working from calculating ϕ(110)=40" Why? What will that have to do with it? Now, on the other hand what is $phi(121)$? And what will THAT have to do with it?
$endgroup$
– fleablood
Jan 29 at 5:17






1




1




$begingroup$
Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
$endgroup$
– Jyrki Lahtonen
Jan 29 at 5:26






$begingroup$
Possible duplicate of How do I compute $a^b,bmod c$ by hand?. IM(NS)HO trusted users inclined to answer this, should check out the mother thread. If they have something new to add to it, post there.
$endgroup$
– Jyrki Lahtonen
Jan 29 at 5:26












2 Answers
2






active

oldest

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$begingroup$

We need $phi(121)=11cdot10implies a^{110}equiv1pmod{121}$ for $11nmid aiff(a,11)=1$



What if $11mid a?$






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$endgroup$





















    1












    $begingroup$

    $phi (110)$ is utterly irrelevent.



    Euler's theorem tells us about $a^k pmod {n}$ and how $k$ and $phi(n)$ relate.



    $phi (k)$ has got sod all to do with fish and fishsticks.



    So we want to know how $110$ and $phi(121)= phi(11^2) = 11(11-1)$ relate.



    How do they relate?



    ....



    So we can break your task into the following.



    1) Figuring out what $phi(121)=phi(11^2) = 11(11-1)$ is.



    2) Figuring how $110$ relates to $phi(121)$. In particular what $100 mod phi(121)$ is.



    3) Figuring if $gcd(a,121)=1$ then what is $110 pmod {phi(121)}equiv a^{(110 %{phi(121)})}$ are for the different values of $a$ so that $gcd(a,121) = 1$.



    4) Figure out what happens when $gcd(a,121) ne 1$.



    Now as the prime factorization of $121 = 11^2$ and $phi(11^2) = 11(11-1)$.....



    Those become fairly easy questions.






    share|cite|improve this answer









    $endgroup$




















      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3












      $begingroup$

      We need $phi(121)=11cdot10implies a^{110}equiv1pmod{121}$ for $11nmid aiff(a,11)=1$



      What if $11mid a?$






      share|cite|improve this answer









      $endgroup$


















        3












        $begingroup$

        We need $phi(121)=11cdot10implies a^{110}equiv1pmod{121}$ for $11nmid aiff(a,11)=1$



        What if $11mid a?$






        share|cite|improve this answer









        $endgroup$
















          3












          3








          3





          $begingroup$

          We need $phi(121)=11cdot10implies a^{110}equiv1pmod{121}$ for $11nmid aiff(a,11)=1$



          What if $11mid a?$






          share|cite|improve this answer









          $endgroup$



          We need $phi(121)=11cdot10implies a^{110}equiv1pmod{121}$ for $11nmid aiff(a,11)=1$



          What if $11mid a?$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 29 at 4:50









          lab bhattacharjeelab bhattacharjee

          228k15158279




          228k15158279























              1












              $begingroup$

              $phi (110)$ is utterly irrelevent.



              Euler's theorem tells us about $a^k pmod {n}$ and how $k$ and $phi(n)$ relate.



              $phi (k)$ has got sod all to do with fish and fishsticks.



              So we want to know how $110$ and $phi(121)= phi(11^2) = 11(11-1)$ relate.



              How do they relate?



              ....



              So we can break your task into the following.



              1) Figuring out what $phi(121)=phi(11^2) = 11(11-1)$ is.



              2) Figuring how $110$ relates to $phi(121)$. In particular what $100 mod phi(121)$ is.



              3) Figuring if $gcd(a,121)=1$ then what is $110 pmod {phi(121)}equiv a^{(110 %{phi(121)})}$ are for the different values of $a$ so that $gcd(a,121) = 1$.



              4) Figure out what happens when $gcd(a,121) ne 1$.



              Now as the prime factorization of $121 = 11^2$ and $phi(11^2) = 11(11-1)$.....



              Those become fairly easy questions.






              share|cite|improve this answer









              $endgroup$


















                1












                $begingroup$

                $phi (110)$ is utterly irrelevent.



                Euler's theorem tells us about $a^k pmod {n}$ and how $k$ and $phi(n)$ relate.



                $phi (k)$ has got sod all to do with fish and fishsticks.



                So we want to know how $110$ and $phi(121)= phi(11^2) = 11(11-1)$ relate.



                How do they relate?



                ....



                So we can break your task into the following.



                1) Figuring out what $phi(121)=phi(11^2) = 11(11-1)$ is.



                2) Figuring how $110$ relates to $phi(121)$. In particular what $100 mod phi(121)$ is.



                3) Figuring if $gcd(a,121)=1$ then what is $110 pmod {phi(121)}equiv a^{(110 %{phi(121)})}$ are for the different values of $a$ so that $gcd(a,121) = 1$.



                4) Figure out what happens when $gcd(a,121) ne 1$.



                Now as the prime factorization of $121 = 11^2$ and $phi(11^2) = 11(11-1)$.....



                Those become fairly easy questions.






                share|cite|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  $phi (110)$ is utterly irrelevent.



                  Euler's theorem tells us about $a^k pmod {n}$ and how $k$ and $phi(n)$ relate.



                  $phi (k)$ has got sod all to do with fish and fishsticks.



                  So we want to know how $110$ and $phi(121)= phi(11^2) = 11(11-1)$ relate.



                  How do they relate?



                  ....



                  So we can break your task into the following.



                  1) Figuring out what $phi(121)=phi(11^2) = 11(11-1)$ is.



                  2) Figuring how $110$ relates to $phi(121)$. In particular what $100 mod phi(121)$ is.



                  3) Figuring if $gcd(a,121)=1$ then what is $110 pmod {phi(121)}equiv a^{(110 %{phi(121)})}$ are for the different values of $a$ so that $gcd(a,121) = 1$.



                  4) Figure out what happens when $gcd(a,121) ne 1$.



                  Now as the prime factorization of $121 = 11^2$ and $phi(11^2) = 11(11-1)$.....



                  Those become fairly easy questions.






                  share|cite|improve this answer









                  $endgroup$



                  $phi (110)$ is utterly irrelevent.



                  Euler's theorem tells us about $a^k pmod {n}$ and how $k$ and $phi(n)$ relate.



                  $phi (k)$ has got sod all to do with fish and fishsticks.



                  So we want to know how $110$ and $phi(121)= phi(11^2) = 11(11-1)$ relate.



                  How do they relate?



                  ....



                  So we can break your task into the following.



                  1) Figuring out what $phi(121)=phi(11^2) = 11(11-1)$ is.



                  2) Figuring how $110$ relates to $phi(121)$. In particular what $100 mod phi(121)$ is.



                  3) Figuring if $gcd(a,121)=1$ then what is $110 pmod {phi(121)}equiv a^{(110 %{phi(121)})}$ are for the different values of $a$ so that $gcd(a,121) = 1$.



                  4) Figure out what happens when $gcd(a,121) ne 1$.



                  Now as the prime factorization of $121 = 11^2$ and $phi(11^2) = 11(11-1)$.....



                  Those become fairly easy questions.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 29 at 5:17









                  fleabloodfleablood

                  73.6k22891




                  73.6k22891















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