How to sort array containing key value pair according to date

-1

Below is array.
What I have to do is sort array according to latest date.
So basically if you look the code after sorting id:12 should come before id:23

I have tried

   myArray.sort(function(a, b) {

   return a.date- b.date;

   });

but it is not working

0:    

{ id: 23

name: "joe"

price: 2300

date: "2018-06-01T09:48:18.000Z"},

1:

{ id: 12

name: "ali"

price: 300

date: "2018-09-01T09:48:1i.000Z"},

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

why sort by time effects id?

– apple apple
Jan 2 at 12:26

add a comment |

-1

Below is array.
What I have to do is sort array according to latest date.
So basically if you look the code after sorting id:12 should come before id:23

I have tried

   myArray.sort(function(a, b) {

   return a.date- b.date;

   });

but it is not working

0:    

{ id: 23

name: "joe"

price: 2300

date: "2018-06-01T09:48:18.000Z"},

1:

{ id: 12

name: "ali"

price: 300

date: "2018-09-01T09:48:1i.000Z"},

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

why sort by time effects id?

– apple apple
Jan 2 at 12:26

add a comment |

-1

Below is array.
What I have to do is sort array according to latest date.
So basically if you look the code after sorting id:12 should come before id:23

I have tried

   myArray.sort(function(a, b) {

   return a.date- b.date;

   });

but it is not working

0:    

{ id: 23

name: "joe"

price: 2300

date: "2018-06-01T09:48:18.000Z"},

1:

{ id: 12

name: "ali"

price: 300

date: "2018-09-01T09:48:1i.000Z"},

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

Below is array.
What I have to do is sort array according to latest date.
So basically if you look the code after sorting id:12 should come before id:23

I have tried

   myArray.sort(function(a, b) {

   return a.date- b.date;

   });

but it is not working

0:    

{ id: 23

name: "joe"

price: 2300

date: "2018-06-01T09:48:18.000Z"},

1:

{ id: 12

name: "ali"

price: 300

date: "2018-09-01T09:48:1i.000Z"},

javascript angular

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

edited Jan 2 at 12:26

asked Jan 2 at 12:24

Mini

asked Jan 2 at 12:24

Mini

asked Jan 2 at 12:24

Mini

why sort by time effects id?

– apple apple
Jan 2 at 12:26

add a comment |

why sort by time effects id?

– apple apple
Jan 2 at 12:26

why sort by time effects id?

– apple apple
Jan 2 at 12:26

add a comment |

2 Answers
2

active

oldest

votes

the following example explains how to sort the array by dates

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

answered Jan 2 at 12:29

user6656728

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

|
show 1 more comment

By using an ISO 8601 compliant date, you could take the strings directly for sorting with String#localeCompare.

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

the following example explains how to sort the array by dates

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

answered Jan 2 at 12:29

user6656728

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

|
show 1 more comment

the following example explains how to sort the array by dates

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

answered Jan 2 at 12:29

user6656728

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

|
show 1 more comment

the following example explains how to sort the array by dates

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

answered Jan 2 at 12:29

user6656728

the following example explains how to sort the array by dates

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

    var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

    array.sort(function(a,b){

      //convert your string into dates

      return new Date(a.date) - new Date(b.date);

    });

    console.log(array)

answered Jan 2 at 12:29

user6656728

answered Jan 2 at 12:29

user6656728

answered Jan 2 at 12:29

user6656728

answered Jan 2 at 12:29

user6656728

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

|
show 1 more comment

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

giving error The left-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type.

– Mini
Jan 2 at 12:30

show me the code you implemented

– user6656728
Jan 2 at 12:32

array.sort(function(a,b){ return new Date(a.date) - new Date(b.date); });

– Mini
Jan 2 at 12:36

I have used ` array = Object.values(obj);`

– Mini
Jan 2 at 12:37

change your array to the following and try again var array=[{'date':'2018-06-05T09:48:18.000Z'},{'date':'2018-06-01T09:48:18.000Z'},{'date':'2018-04-01T09:48:18.000Z'}];

– user6656728
Jan 2 at 12:48

|
show 1 more comment

By using an ISO 8601 compliant date, you could take the strings directly for sorting with String#localeCompare.

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

add a comment |

By using an ISO 8601 compliant date, you could take the strings directly for sorting with String#localeCompare.

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

add a comment |

By using an ISO 8601 compliant date, you could take the strings directly for sorting with String#localeCompare.

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

By using an ISO 8601 compliant date, you could take the strings directly for sorting with String#localeCompare.

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

var array =  [{ id: 23, name: "joe", price: 2300, date: "2018-06-01T09:48:18.000Z" }, { id: 12, name: "ali", price: 300, date: "2018-09-01T09:48:1i.000Z" }];



array.sort(function(a, b) {

    return b.date.localeCompare(a.date); // desc

});



console.log(array);

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

edited Jan 2 at 12:45

answered Jan 2 at 12:25

Nina Scholz

193k15106177

answered Jan 2 at 12:25

Nina Scholz

193k15106177

answered Jan 2 at 12:25

Nina Scholz

193k15106177

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

add a comment |

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

It is partially sorting data according to date.

– Mini
Jan 2 at 12:42

add a comment |

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