Remove number from list in which difference between two number are less then specific number

-4

a = [2, 5, 6, 12, 21, 25, 32, 41]

This is my list and I want to remove all the numbers which are not in difference of 7.

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

1

Can you please share the output of the above list.

– Mayank Bansal
Jan 2 at 12:32

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:26

add a comment |

-4

a = [2, 5, 6, 12, 21, 25, 32, 41]

This is my list and I want to remove all the numbers which are not in difference of 7.

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

1

Can you please share the output of the above list.

– Mayank Bansal
Jan 2 at 12:32

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:26

add a comment |

-4

a = [2, 5, 6, 12, 21, 25, 32, 41]

This is my list and I want to remove all the numbers which are not in difference of 7.

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

a = [2, 5, 6, 12, 21, 25, 32, 41]

This is my list and I want to remove all the numbers which are not in difference of 7.

python-3.x

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

edited Jan 2 at 15:12

Diptangsu Goswami

782921

edited Jan 2 at 15:12

Diptangsu Goswami

782921

edited Jan 2 at 15:12

Diptangsu Goswami

782921

asked Jan 2 at 12:19

Manohar Sonwan

asked Jan 2 at 12:19

Manohar Sonwan

asked Jan 2 at 12:19

Manohar Sonwan

1

Can you please share the output of the above list.

– Mayank Bansal
Jan 2 at 12:32

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:26

add a comment |

1

Can you please share the output of the above list.

– Mayank Bansal
Jan 2 at 12:32

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:26

Can you please share the output of the above list.

– Mayank Bansal
Jan 2 at 12:32

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:26

add a comment |

2 Answers
2

active

oldest

votes

Before diving into the answers, let's go over what we're dealing with.

You got a list 'A', which you need to loop through to get a list of numbers that are greater than the previous value + 7

If you boil down the question, you get left with two main goals

We need a loop

and we have a list with the final answer

There are two generic ways of approaching this question. In a loop, we populate a new list. The second way is to manipulate the original list.
Although the First approach requires additional memory, I'll be using the First approach for simplicity.

a = [2, 5, 6, 12, 21, 25, 32, 41]     # your original list

b =            # Empty list that will contain final product



for i in range(len(a)):

    if len(b) == 0:       # if the list is empty, we add first item from 'a' (In our example, it'll be 2)

        b.append(a[i])

    else:

        if a[i] > b[len(b)-1]+7 or a[i] < b[len(b)-1]-7:   # for every value of a, we compare the last digit from list b

            b.append(a[i])

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

add a comment |

-1

As far as I have understood your question, in your output list, only those elements should be there whose sum is 7. So that can be achieved by

i=1;

while i<len(a):

    if(a[i]-a[i-1] < 7):

        a.remove(a[i])

    else:

        i+=1

print(a)

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

|
show 4 more comments

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Before diving into the answers, let's go over what we're dealing with.

You got a list 'A', which you need to loop through to get a list of numbers that are greater than the previous value + 7

If you boil down the question, you get left with two main goals

We need a loop

and we have a list with the final answer

a = [2, 5, 6, 12, 21, 25, 32, 41]     # your original list

b =            # Empty list that will contain final product



for i in range(len(a)):

    if len(b) == 0:       # if the list is empty, we add first item from 'a' (In our example, it'll be 2)

        b.append(a[i])

    else:

        if a[i] > b[len(b)-1]+7 or a[i] < b[len(b)-1]-7:   # for every value of a, we compare the last digit from list b

            b.append(a[i])

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

add a comment |

Before diving into the answers, let's go over what we're dealing with.

You got a list 'A', which you need to loop through to get a list of numbers that are greater than the previous value + 7

If you boil down the question, you get left with two main goals

We need a loop

and we have a list with the final answer

a = [2, 5, 6, 12, 21, 25, 32, 41]     # your original list

b =            # Empty list that will contain final product



for i in range(len(a)):

    if len(b) == 0:       # if the list is empty, we add first item from 'a' (In our example, it'll be 2)

        b.append(a[i])

    else:

        if a[i] > b[len(b)-1]+7 or a[i] < b[len(b)-1]-7:   # for every value of a, we compare the last digit from list b

            b.append(a[i])

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

add a comment |

Before diving into the answers, let's go over what we're dealing with.

You got a list 'A', which you need to loop through to get a list of numbers that are greater than the previous value + 7

If you boil down the question, you get left with two main goals

We need a loop

and we have a list with the final answer

a = [2, 5, 6, 12, 21, 25, 32, 41]     # your original list

b =            # Empty list that will contain final product



for i in range(len(a)):

    if len(b) == 0:       # if the list is empty, we add first item from 'a' (In our example, it'll be 2)

        b.append(a[i])

    else:

        if a[i] > b[len(b)-1]+7 or a[i] < b[len(b)-1]-7:   # for every value of a, we compare the last digit from list b

            b.append(a[i])

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

Before diving into the answers, let's go over what we're dealing with.

You got a list 'A', which you need to loop through to get a list of numbers that are greater than the previous value + 7

If you boil down the question, you get left with two main goals

We need a loop

and we have a list with the final answer

a = [2, 5, 6, 12, 21, 25, 32, 41]     # your original list

b =            # Empty list that will contain final product



for i in range(len(a)):

    if len(b) == 0:       # if the list is empty, we add first item from 'a' (In our example, it'll be 2)

        b.append(a[i])

    else:

        if a[i] > b[len(b)-1]+7 or a[i] < b[len(b)-1]-7:   # for every value of a, we compare the last digit from list b

            b.append(a[i])

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

edited Jan 10 at 13:04

answered Jan 2 at 14:58

Hannest

513

answered Jan 2 at 14:58

Hannest

513

answered Jan 2 at 14:58

Hannest

513

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

add a comment |

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

thank you, it was very helpful

– Manohar Sonwan
Jan 9 at 12:28

add a comment |

-1

As far as I have understood your question, in your output list, only those elements should be there whose sum is 7. So that can be achieved by

i=1;

while i<len(a):

    if(a[i]-a[i-1] < 7):

        a.remove(a[i])

    else:

        i+=1

print(a)

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

|
show 4 more comments

-1

As far as I have understood your question, in your output list, only those elements should be there whose sum is 7. So that can be achieved by

i=1;

while i<len(a):

    if(a[i]-a[i-1] < 7):

        a.remove(a[i])

    else:

        i+=1

print(a)

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

|
show 4 more comments

-1

As far as I have understood your question, in your output list, only those elements should be there whose sum is 7. So that can be achieved by

i=1;

while i<len(a):

    if(a[i]-a[i-1] < 7):

        a.remove(a[i])

    else:

        i+=1

print(a)

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

As far as I have understood your question, in your output list, only those elements should be there whose sum is 7. So that can be achieved by

i=1;

while i<len(a):

    if(a[i]-a[i-1] < 7):

        a.remove(a[i])

    else:

        i+=1

print(a)

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

edited Jan 2 at 14:24

answered Jan 2 at 12:52

Mayank Bansal

408215

answered Jan 2 at 12:52

Mayank Bansal

408215

answered Jan 2 at 12:52

Mayank Bansal

408215

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

|
show 4 more comments

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

This is I want the output:

– Manohar Sonwan
Jan 2 at 13:21

This is I want the output: a = [2, 12, 21,32,41]

– Manohar Sonwan
Jan 2 at 13:22

@ManoharSonwan I have updated my Answer.

– Mayank Bansal
Jan 2 at 13:41

My question is, a difference between any two number should be greater than 7.

– Manohar Sonwan
Jan 2 at 13:51

this gives output [2, 6, 12, 21, 32, 41], here difference between 2, 6 is 4 and 6 to 12 is 6

– Manohar Sonwan
Jan 2 at 13:52

|
show 4 more comments

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