Mixing
Matrix in which rows are coordinates of points of a meshgrid
0
In this tutorial I find code like
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
Y, X = np.meshgrid(y, x)
xy = np.vstack([X.ravel(), Y.ravel()]).T
print(xy)
Isn't there a shorter way to get a matrix where rows are coordinates of points of the meshgrid, than using meshgrid+vstack+ravel+transpose?
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
...
python arrays numpy mesh
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
add a comment |
0
In this tutorial I find code like
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
Y, X = np.meshgrid(y, x)
xy = np.vstack([X.ravel(), Y.ravel()]).T
print(xy)
Isn't there a shorter way to get a matrix where rows are coordinates of points of the meshgrid, than using meshgrid+vstack+ravel+transpose?
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
...
python arrays numpy mesh
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20
add a comment |
0
0
0
In this tutorial I find code like
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
Y, X = np.meshgrid(y, x)
xy = np.vstack([X.ravel(), Y.ravel()]).T
print(xy)
Isn't there a shorter way to get a matrix where rows are coordinates of points of the meshgrid, than using meshgrid+vstack+ravel+transpose?
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
...
python arrays numpy mesh
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
In this tutorial I find code like
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
Y, X = np.meshgrid(y, x)
xy = np.vstack([X.ravel(), Y.ravel()]).T
print(xy)
Isn't there a shorter way to get a matrix where rows are coordinates of points of the meshgrid, than using meshgrid+vstack+ravel+transpose?
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
...
python arrays numpy mesh
python arrays numpy mesh
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
asked Nov 22 '18 at 8:47
BasjBasj
6,18632107233
6,18632107233
Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20
add a comment |
Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20
Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20
add a comment |
2 Answers
2
active
oldest
votes
2
You can skip meshgrid and get what you want more directly by just taking the cartesian product of x and y:
from itertools import product
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.array(list(product(x,y)))
print(xy)
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
[-4.47368421 -0.55555556]
[-4.47368421 -0.33333333]
...
]
answered Nov 22 '18 at 9:51
teltel
7,41621431
add a comment |
1
Here is implementation with repeat and tile methods.
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.empty((len(x) * len(y), 2))
xy[:, 0] = np.repeat(x, len(y))
xy[:, 1] = np.tile(y, len(x))
print(xy)
I suppose meshgrid method uses same approach to fill it's result matrix.
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can skip meshgrid and get what you want more directly by just taking the cartesian product of x and y:
from itertools import product
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.array(list(product(x,y)))
print(xy)
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
[-4.47368421 -0.55555556]
[-4.47368421 -0.33333333]
...
]
answered Nov 22 '18 at 9:51
teltel
7,41621431
add a comment |
2
You can skip meshgrid and get what you want more directly by just taking the cartesian product of x and y:
from itertools import product
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.array(list(product(x,y)))
print(xy)
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
[-4.47368421 -0.55555556]
[-4.47368421 -0.33333333]
...
]
answered Nov 22 '18 at 9:51
teltel
7,41621431
add a comment |
2
2
2
You can skip meshgrid and get what you want more directly by just taking the cartesian product of x and y:
from itertools import product
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.array(list(product(x,y)))
print(xy)
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
[-4.47368421 -0.55555556]
[-4.47368421 -0.33333333]
...
]
answered Nov 22 '18 at 9:51
teltel
7,41621431
You can skip meshgrid and get what you want more directly by just taking the cartesian product of x and y:
from itertools import product
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.array(list(product(x,y)))
print(xy)
Output:
[[-5. -1. ]
[-5. -0.77777778]
[-5. -0.55555556]
[-5. -0.33333333]
[-5. -0.11111111]
[-5. 0.11111111]
[-5. 0.33333333]
[-5. 0.55555556]
[-5. 0.77777778]
[-5. 1. ]
[-4.47368421 -1. ]
[-4.47368421 -0.77777778]
[-4.47368421 -0.55555556]
[-4.47368421 -0.33333333]
...
]
answered Nov 22 '18 at 9:51
teltel
7,41621431
answered Nov 22 '18 at 9:51
teltel
7,41621431
answered Nov 22 '18 at 9:51
teltel
7,41621431
answered Nov 22 '18 at 9:51
teltel
7,41621431
7,41621431
add a comment |
add a comment |
1
Here is implementation with repeat and tile methods.
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.empty((len(x) * len(y), 2))
xy[:, 0] = np.repeat(x, len(y))
xy[:, 1] = np.tile(y, len(x))
print(xy)
I suppose meshgrid method uses same approach to fill it's result matrix.
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
add a comment |
1
Here is implementation with repeat and tile methods.
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.empty((len(x) * len(y), 2))
xy[:, 0] = np.repeat(x, len(y))
xy[:, 1] = np.tile(y, len(x))
print(xy)
I suppose meshgrid method uses same approach to fill it's result matrix.
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
add a comment |
1
1
1
Here is implementation with repeat and tile methods.
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.empty((len(x) * len(y), 2))
xy[:, 0] = np.repeat(x, len(y))
xy[:, 1] = np.tile(y, len(x))
print(xy)
I suppose meshgrid method uses same approach to fill it's result matrix.
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
Here is implementation with repeat and tile methods.
import numpy as np
x = np.linspace(-5, 5, 20)
y = np.linspace(-1, 1, 10)
xy = np.empty((len(x) * len(y), 2))
xy[:, 0] = np.repeat(x, len(y))
xy[:, 1] = np.tile(y, len(x))
print(xy)
I suppose meshgrid method uses same approach to fill it's result matrix.
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
answered Nov 23 '18 at 10:28
AnteAnte
4,39451942
4,39451942
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
add a comment |
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
For future reference: docs.scipy.org/doc/numpy-1.15.0/reference/generated/…
– Basj
Nov 23 '18 at 12:54
add a comment |
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Numpy.repeat() for x and numpy.tile() for y coordinate.
– Ante
Nov 23 '18 at 8:10
@ante can you post it as an answer with code example?
– Basj
Nov 23 '18 at 9:43
@Bajs I posted answer with a code.
– Ante
Nov 23 '18 at 11:20