Asymptotics complexity comparison












0












$begingroup$


I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:



$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$



$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$



I'm leaning towards $Theta$ but with no clear explanation.



Any tips greatly appreciated!










share|cite|improve this question











$endgroup$












  • $begingroup$
    Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
    $endgroup$
    – Alex R.
    Jan 28 at 21:53


















0












$begingroup$


I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:



$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$



$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$



I'm leaning towards $Theta$ but with no clear explanation.



Any tips greatly appreciated!










share|cite|improve this question











$endgroup$












  • $begingroup$
    Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
    $endgroup$
    – Alex R.
    Jan 28 at 21:53
















0












0








0





$begingroup$


I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:



$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$



$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$



I'm leaning towards $Theta$ but with no clear explanation.



Any tips greatly appreciated!










share|cite|improve this question











$endgroup$




I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:



$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$



$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$



I'm leaning towards $Theta$ but with no clear explanation.



Any tips greatly appreciated!







asymptotics computational-complexity






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 30 at 3:41









Flying Dogfish

26612




26612










asked Jan 28 at 21:48









kommkomm

11




11












  • $begingroup$
    Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
    $endgroup$
    – Alex R.
    Jan 28 at 21:53




















  • $begingroup$
    Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
    $endgroup$
    – Alex R.
    Jan 28 at 21:53


















$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53






$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53












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