Asymptotics complexity comparison
$begingroup$
I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:
$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$
$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$
I'm leaning towards $Theta$ but with no clear explanation.
Any tips greatly appreciated!
asymptotics computational-complexity
$endgroup$
add a comment |
$begingroup$
I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:
$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$
$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$
I'm leaning towards $Theta$ but with no clear explanation.
Any tips greatly appreciated!
asymptotics computational-complexity
$endgroup$
$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53
add a comment |
$begingroup$
I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:
$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$
$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$
I'm leaning towards $Theta$ but with no clear explanation.
Any tips greatly appreciated!
asymptotics computational-complexity
$endgroup$
I'm having trouble finding out which of the following are either $O$, $Omega$ or $Theta$:
$2^{{n^2}+{sqrt{ log n}}}$ compared to $2^{n^2}$- $sqrt n$
$2^{{n^2}+{sqrt{log n}}}$ compared to $2^{n^2}$
I'm leaning towards $Theta$ but with no clear explanation.
Any tips greatly appreciated!
asymptotics computational-complexity
asymptotics computational-complexity
edited Jan 30 at 3:41
Flying Dogfish
26612
26612
asked Jan 28 at 21:48
kommkomm
11
11
$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53
add a comment |
$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53
$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53
$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53
add a comment |
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$begingroup$
Try dividing the the first by the second and studying the resulting quantity. It should be straightforward for your second question.
$endgroup$
– Alex R.
Jan 28 at 21:53