Mixing
Schramm Loewner evolution
$begingroup$
I read on Conformally Invariant Processes in the Plane that the $SLE_k$ are generated by a path, what does it mean?
I know that for $k le 4$ the $mathbb{H}$-hulls associated is a simple curve, but in the other cases i don't think it is still a curve...
Someone help me please
probability-theory
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
$endgroup$
add a comment |
$begingroup$
I read on Conformally Invariant Processes in the Plane that the $SLE_k$ are generated by a path, what does it mean?
I know that for $k le 4$ the $mathbb{H}$-hulls associated is a simple curve, but in the other cases i don't think it is still a curve...
Someone help me please
probability-theory
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
$endgroup$
$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43
add a comment |
$begingroup$
I read on Conformally Invariant Processes in the Plane that the $SLE_k$ are generated by a path, what does it mean?
I know that for $k le 4$ the $mathbb{H}$-hulls associated is a simple curve, but in the other cases i don't think it is still a curve...
Someone help me please
probability-theory
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
$endgroup$
I read on Conformally Invariant Processes in the Plane that the $SLE_k$ are generated by a path, what does it mean?
I know that for $k le 4$ the $mathbb{H}$-hulls associated is a simple curve, but in the other cases i don't think it is still a curve...
Someone help me please
probability-theory
probability-theory
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
asked Jan 28 at 22:33
Claudio DelfinoClaudio Delfino
63
63
$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43
add a comment |
$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43
$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43
$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43
add a comment |
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$begingroup$
My guess is that $K_t$ is equal to $gamma(0,t]$ union the bounded connected component of $mathbb{H} setminus gamma(0,t]$, but i don' t know if it is ok
$endgroup$
– Claudio Delfino
Jan 28 at 22:43